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2 years ago

8

On the grid below, which point is located in the quadrant where the x- and y-coordinates are both negative numbers?

2 answers:

lana66690 [7]2 years ago

8 0

it would be C uebeuwuehejwuhdbeuwuwbdjdjd

Gnom [1K]2 years ago

3 0

Answer : c
explanation : because i said so

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Melanie draws with great fervor, using up pencils at an incredible rate: 14 pencils every

AfilCa [17]

4 pencils . 4/9 of an hour = 4/9 of 60 minutes = 4/9 * 60 = 80/3 minutes
x pencils = ? . one hour = 60 minutes

14 * 60 = 80/3 * x /*3
14 * 60 * 3 = 80 * x
80 * x = 2520 /80
x = 2520 / 80
x = 31.5 pencils

The result would be 32 pencils in one hour.

5 0

3 years ago

Find the standard deviation of 21, 31, 26, 24, 28, 26

Vesnalui [34]

Given the dataset

$x = \{21,\ 31,\ 26,\ 24,\ 28,\ 26\}$

We start by computing the average:

$\overline{x} = \dfrac{21+31+26+24+28+26}{6}=\dfrac{156}{6}=26$

We compute the difference bewteen each element and the average:

$x-\overline{x} = \{-6,\ 5,\ 0,\ -2,\ 2,\ 0\}$

We square those differences:

$(x-\overline{x})^2 = \{36,\ 25,\ 0,\ 4,\ 4,\ 0\}$

And take the average of those squared differences: we sum them

$\displaystyle \sum_{i=1}^n (x-\overline{x})^2=36+25+4+4+0+0=69$

And we divide by the number of elements:

$\displaystyle \sigma^2=\dfrac{\sum_{i=1}^n (x-\overline{x})^2}{n} = \dfrac{69}{6} = 11.5$

Finally, we take the square root of this quantity and we have the standard deviation:

$\displaystyle\sigma = \sqrt{\dfrac{\sum_{i=1}^n (x-\overline{x})^2}{n}} = \sqrt{11.5}\approx 3.39$

8 0

3 years ago

Please help asap!!! i dont understand it

pshichka [43]

Answer:

a

Step-by-step explanation:

A perpendicular bisector, intersects a line at its mid point and is perpendicular to it.

Calculate slope m using the slope formula

m = $\frac{y_{2}-y_{1} }{x_{2}-x_{1} }$

with (x₁, y₁ ) = (- 7, 1) and (x₂, y₂ ) = (9, 13)

m = $\frac{13-1}{9-(-7)}$ = $\frac{12}{9+7}$ = $\frac{12}{16}$ = $\frac{3}{4}$

Given a line with slope m then the slope of a line perpendicular to it is

$m_{perpendicular}$ = - $\frac{1}{m}$ = - $\frac{1}{\frac{3}{4} }$ = - $\frac{4}{3}$ ← slope of perpendicular bisector

Given endpoints (x₁, y₁ ) and (x₂, y₂ ) then the midpoint is

( $\frac{x_{1}+x_{2} }{2}$ , $\frac{y_{1}+y_{2} }{2}$ )

using (x₁, y₁ ) = (- 7, 1) and (x₂, y₂ ) = (9, 13) , then

midpoint = ( $\frac{-7+9}{2}$ , $\frac{1+13}{2}$ ) = ( $\frac{2}{2}$ , $\frac{14}{2}$ ) = (1, 7 )

The equation of a line in slope- intercept form is

y = mx + c ( m is the slope and c the y- intercept )

Here m = - $\frac{4}{3}$ , then

y = - $\frac{4}{3}$ x + c ← is the partial equation

To find c substitute the midpoint (1, 7) into the partial equation

7 = - $\frac{4}{3}$ + c ⇒ c = $\frac{21}{3}$ + $\frac{4}{3}$ = $\frac{25}{3}$

y = - $\frac{4}{3}$ x + $\frac{25}{3}$ ← equation of perpendicular bisector

7 0

2 years ago

A frosting is made of cream cheese and powdered sugar in the ratio 3:2. If you use 120g or cream cheese, how much powdered sugar

siniylev [52]

Answer: 80 g

Step-by-step explanation:

Given

The frosting is made of cream cheese and Powdered sugar in the ratio of 3:2.

If 120 g of cheese is used

Assume the quantity of powdered sugar is x

So, we can write the ratio as

$\Rightarrow \dfrac{3}{2}=\dfrac{120}{x}\\\\\Rightarrow x=\dfrac{2}{3}\times 120\\\\\Rightarrow x=\dfrac{2}{3}\times 3\times 40\\\\\Rightarrow x=80\ g$

So, 80 g of powdered sugar is used.

3 0

3 years ago

Read 2 more answers

Can someone that is good at 7th grade math help me plzzzz

stiks02 [169]

Answer:

-4 *-4 *-4

= 16*-4

= ANWSER

-9*-9

=81

Step-by-step explanation:

6 0

3 years ago