Answer:
A sample of 997 is needed.
Step-by-step explanation:
In a sample with a number n of people surveyed with a probability of a success of
, and a confidence level of
, we have the following confidence interval of proportions.
In which
z is the z-score that has a p-value of
.
The margin of error is of:

A previous study indicates that the proportion of left-handed golfers is 8%.
This means that 
98% confidence level
So
, z is the value of Z that has a p-value of
, so
.
How large a sample is needed in order to be 98% confident that the sample proportion will not differ from the true proportion by more than 2%?
This is n for which M = 0.02. So






Rounding up:
A sample of 997 is needed.
Answer:
0.04 or 4%
Step-by-step explanation:
point estimate of proportion:
(0.6+0.68)/2
1.28/2
0.64
Margin of error:
0.68 - 0.64 = 0.04
0.04×100 = 4%
This graph shifted down 4 units would be y = x^2 - 2.
Different shifts in standard graphs each have to be done in their own way. Shifting up and down is done by manipulating the y-intercept, which is the number at the end of the equation. Since we started at +2 and it is going down 4, it brings us to -2.
Answer:
a) 
Step-by-step explanation:
<u><em>Step(i):-</em></u>
Given that A and B are independent events
P(A∩B) =P(A) P(B)
we will use the conditional probability

or
<u></u>
<u> Step(ii):-</u>
Given that A and B are independent events
P(A∩B) =P(A) P(B)
<u></u>

