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2 years ago

If two angles are supplementary and one angle measures 47°, what is the measure of the other angle?

Mathematics

2 answers:

Elina [12.6K]2 years ago

4 0

Answer:

133 degrees

Step-by-step explanation:

X+47=180

X=133

Kisachek [45]2 years ago

3 0

Answer:

133 degrees.

Step-by-step explanation:

Supplementary means the angles at to 180 degrees, so you would subtract 47 from 180 and get 133 degrees.

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Find f(x) and g(x) so that the function can be described as y = f(g(x)). y = 7/sqrt 8x +10

Blizzard [7]

Assuming you meant

$y = \frac{7}{ \sqrt{8x+10} }$

Then you can compose the function g(x)

$g(x)= \sqrt{8x+10}$

With the function

$f(x)= \frac{7}{x}$

Because f (g(x) ) means that you first find (calculte) $\sqrt{8x+10}$ and second you divide 7 by g(x) to obtain 7 / [√(8x+10) ].

8 0

3 years ago

Can you help me answer this? please

Leya [2.2K]

Answer: 1859.5 mini bears

Step-by-step explanation:

From the information given in the question,

10 mini bars = 12.1 grams

10 regular bars = 23.1 gram

1 super bear = 2250 grams

To eat enough mini bears to match the super bears, the number that it'll take will be:

Since 10 mini bars = 12.1 grams

1 mini bear = 12.1 grams / 10 = 1.21 gram

Since 1 super bear = 2250 grams, the number of mini bears needed to equate this will be:

= 2250/1.21

= 1859.5 mini bears

5 0

2 years ago

HELLOOOO HELP PLEASE

MA_775_DIABLO [31]

Answer:

$2*log(x)+log(y)$

Step-by-step explanation:

So, there are two logarithmic identities you're going to need to know.

Logarithm of a power:

$log_ba^c=c*log_ba$

So to provide a quick proof and intuition as to why this works, let's consider the following logarithm: $log_ba=x\implies b^x=a$

Now if we raise both sides to the power of c, we get the following equation: $(b^x)^c=a^c$

Using the exponential identity: $(x^a)^c=x^{a*c}$

We get the equation: $b^{xc}=a^c$

If we convert this back into logarithmic form we get: $log_ba^c=x*c$

Since x was the basic logarithm we started with, we substitute it back in, to get the equation: $log_ba^c=c*log_ba$

Now the second logarithmic property you need to know is

The Logarithm of a Product:

$log_b{ac}=log_ba+log_bc$

Now for a quick proof, let's just say: $x=log_ba\text{ and }y=log_bc$

Now rewriting them both in exponential form, we get the equations:

$b^x=a\\b^y=c$

We can multiply a * c, and since b^x = a, and b^y = c, we can substitute that in for a * c, to get the following equation:

$b^x*b^y=a*c$

Using the exponential identity: $x^{a}*x^b=x^{a+b}$ , we can rewrite the equation as:

$b^{x+y}=ac$

taking the logarithm of both sides, we get:

$log_bac=x+y$

Since x and y are just the logarithms we started with, we can substitute them back in to get: $log_bac=log_ba+log_bc$

Now let's use these identities to rewrite the equation you gave

$log(x^2y)$

As you can see, this is a log of products, so we can separate it into two logarithms (with the same base)

$log(x^2)+log(y)$

Now using the logarithm of a power to rewrite the log(x^2) we get:

$2*log(x)+log(y)$

3 0

1 year ago

(- 1, 2) and (9, - 3)

slava [35]

9/5

the distance is 9 over, and 5 up.

5 0

2 years ago

Read 2 more answers

Solve for x.38(2x+16)−2=13 Enter your answer in the box.x =

lys-0071 [83]

Given:

$\frac{3}{8}(2x+16)-2=13$ $\frac{3}{8}(2x+16)=13+2$ $\frac{3}{8}(2x+16)=15$ $(2x+16)=15\times\frac{8}{3}$ $(2x+16)=40$ $2x=40-16$ $2x=24$ $x=\frac{24}{2}$ $x=12$

5 0

1 year ago