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vazorg [7]
3 years ago
10

For each function, what is the output of the given input? . . For f(x) = 4x + 7, find f(4)

Mathematics
1 answer:
RideAnS [48]3 years ago
7 0
Look at the LHS in f(x) = 4x + 7, ie, f(x). Compare it with f(4). You see that we've put 4 in place of x. 
<span>To find f(4), put 4 in place of x in RHS. Simple. </span>

<span>f(4) = 4 * 4 + 7 = 16 + 7 = 23.</span>
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This is C. cos Z = sin (90 - Y)
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To find a power series for the function, centered at 0. f(x) = 18 (x + 1)3
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Consider this option; make a design according to the local requirements.

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{4x-2y+5z=6 <br> {3x+3y+8z=4 <br> {x-5y-3z=5
lesya692 [45]

There are three possible outcomes that you may encounter when working with these system of equations:


  •    one solution
  •    no solution
  •    infinite solutions

We are going to try and find values of x, y, and z that will satisfy all three equations at the same time. The following are the equations:

  1. 4x-2y+5z = 6
  2. 3x+3y+8z = 4
  3. x-5y-3z = 5

We are going to use elimination(or addition) method

Step 1: Choose to eliminate any one of the variables from any pair of equations.

In this case it looks like if we multiply the third equation by 4 and  subtracting it from equation 1, it will be fairly simple to eliminate the x term from the first and third equation.

So multiplying Left Hand Side(L.H.S) and Right Hand Side(R.H.S) of 3rd equation with 4 gives us a new equation 4.:

4. 4x-20y-12z = 20      

Subtracting eq. 4 from Eq. 1:

(L.HS) : 4x-2y+5z-(4x-20y-12z) = 18y+17z

(R.H.S) : 20 - 6 = 14

5. 18y+17z=14

Step 2:  Eliminate the SAME variable chosen in step 2 from any other pair of equations, creating a system of two equations and 2 unknowns.

Similarly if we multiply 3rd equation with 3 and then subtract it from eq. 2 we get:

(L.HS) : 3x+3y+8z-(3x-15y-9z) = 18y+17z

(R.H.S) : 4 - 15 = -11

6. 18y+17z = -11

Step 3:  Solve the remaining system of equations 6 and 5 found in step 2 and 1.

Now if we try to solve equations 5 and 6 for the variables y and z. Subtracting eq 6 from eq. 5 we get:

(L.HS) : 18y+17z-(18y+17z) = 0

(R.HS) : 14-(-11) = 25

0 = 25

which is false, hence no solution exists



3 0
3 years ago
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Murljashka [212]

Answer:

-76.07

Step-by-step explanation:

-24-(41.07+11)

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-24-41.07 + 11

-24-41.07-11

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