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3 years ago

What is really critical for the y - intercept? Please answer

Mathematics

2 answers:

ANEK [815]3 years ago

8 0

Answer:

That it satisfies x = 0

Step-by-step explanation:

The y-intercept is whatever the y-value is when the x-value is zero, therefore if the x-value is anything other than 0, you can't have the y-intercept value.

KengaRu [80]3 years ago

3 0

Answer: 0

Step-by-step explanation:

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Probability word problem

Crazy boy [7]

Answer:

see below

Step-by-step explanation:

A can speak french

There are 10 students who can speak french, 4 girls and 6 boys

P(french) = speak french/ total

= 10/30

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B is a boy

There are 16 boys

P (boy) = boys/total

= 16/30

8/15

C girl who can speak french

There are 4 girls who can speak french

P (girl who can speak french) = girl who can speak french/ total

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3 years ago

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Answer:

Step-by-step explanation:

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3 years ago

Please help me I have been stuck on this question for ages

Finger [1]

Answer:28 green and 35 red

Step-by-step explanation:

Given

If there are r red counter and g green counter then

Probability of drawing a green counter is $P(g)=\frac{4}{9}$

and $P(g)=\frac{\text{No of g counter}}{\text{Total no of counter}}$

Thus $\frac{\text{No of g counter}}{\text{Total no of counter}}=\frac{4}{9}$

$\frac{g}{g+r}=\frac{4}{9}$

$\Rightarrow 9g=4g+4r$

$\Rightarrow 5g=4r\quad \ldots(i)$

Also if 4 red and 2 green counter is added the probability of drawing a green counter is

$P(g)=\frac{10}{23}=\frac{\text{No of g counter}}{\text{Total no of counter}}$

$\Rightarrow \frac{10}{23}=\frac{g+2}{g+2+r+4}$

$\Rightarrow \frac{10}{23}=\frac{g+2}{g+r+6}$

$\Rightarrow 10g+10r+60=23g+46$

$\Rightarrow 10r+14=13g\ quad \ldots(ii)$

Substitute the value of g in equation (ii)[/tex]

$\Rightarrow 10\times \frac{5}{4}g+14=13g$

$\Rightarrow \frac{25}{2}g+14=13g$

$\Rightarrow g=28$

Therefore $r=35$

Thus there 28 green counter and 35 red counter

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3 years ago

Andy and Jordan's are playing a game that involves tossing two dice numbered one to six, and recording the sum of the two how ma

Ne4ueva [31]

Answer:

there are 11 diffrent sums and the greatest sum is 12

Step-by-step explanation:

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3 years ago

Can you please show me how to do:

USPshnik [31]

Step-by-step explanation:

$6\sqrt3\cdot\dfrac{\sqrt3}{3}=\dfrac{(6\sqrt3)(\sqrt3)}{3}\\\\\text{use the associative property}\ (a\times b)\times c=a\times(b\times c)\\\\=\dfrac{(6)(\sqrt3\cdot\sqrt3)}{3}\\\\\text{use}\ \sqrt{a}\cdot\sqrt{a}=a\\\\=\dfrac{(6)(\not3)}{\not3}\qquad\text{cancel 3}\\\\=6$

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3 years ago

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