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marishachu [46]

3 years ago

10

Sixty-seven biscuits are to be fed to 10 pets; each pet is either a cat or a dog. Each dog is to get seven biscuits, and each ca

t is to get six. How many dogs are there?

1 answer:

VLD [36.1K]3 years ago

3 0

Answer:

There are 7 dogs.

Step-by-step explanation:

7 (dogs) x 7 (biscuits) = 49

3 (cats) x 6 (biscuits) = 18

49 + 18 = 67

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2 years ago

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In 1990, the population of Boston, Massachusetts was 574,283. In 2000, the population was 589,141. What is the percent of change

MrMuchimi

Answer:

Percent of change in population is $2.6$ %

Step-by-step explanation:

Given population of Boston is $574,283$ measured in year $1990$ .

And population of Boston in year $2000$ is $589,141$ .

We need to find percent of change in population.

So, percent change $=\frac{New\ population-Old\ population}{Old\ population}\times100$ %

Here old population is $574,283$ and new population is $589,141$

Plugging these value in formula we get,

Percent change $=\frac{589,141-574,283}{574,283}\times100\\\\=\frac{14858}{574,283}\times100=0.0258\times100\\\\=2.587$

Rounding to nearest tenth 2.6%

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3 years ago