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frozen [14]
4 years ago
15

Solve quadratic equation by factoring X^2 + 7x +10=0

Mathematics
1 answer:
miss Akunina [59]4 years ago
6 0
There’s your answer:)

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Let a, b, c be the lengths of sides of a triangle; a=4.8, b=0.23, and c is a whole number. Find c.
BaLLatris [955]

\sqrt{4.8 {}^2{ +0.23 {}^{2} } }
If you solve it, the answer will be

C= 4.80

Seeing as its supposed to be a whole number, you will round up, so it will be 5
4 0
3 years ago
5. Barb exercises for 22 hours each week.
romanna [79]

Answer:

308 hours?

Step-by-step explanation:

Simple multiplication is good with a calculator.

8 0
3 years ago
Solve the system of equations
nikitadnepr [17]
The solution is A

x=2 y=-1

the solution is where the two lines intersect

5 0
3 years ago
Read 2 more answers
is a stem and leaf plot or a bar graph appropriate to display the number of students at three schools? explain your choice
Dominik [7]
Bar graph because a stem and leaf plot is used when there are big numbers and also when there is a lot of numbers. It CANNOT be used for comparing different data.

Bar graphs are used to compare data. To be more specific, you should use a double bar graph because:

Double bar graphs have 2 or more bars for compariong
Bar graphs are usually used to show length

Answer: Double bar graph (bar graph)

Hope this helps :)
4 0
4 years ago
Read 2 more answers
The half-life of a certain radioactive element is 35 hours. If there are 904 grams of this element, how much will be left after
Cloud [144]
<h3>Answer: 226 grams</h3>

===========================================================

Explanation:

The half-life is 35 hours. This means every 35 hours, the amount of the substance is cut in half. If we started with 100 grams, then 35 hours later, we will have 50 grams. Then another 35 hours later we will then have 25 grams, and so on.

In this case, we start with 904 grams and follow this sequence:

904, 452, 226, 113, ...

Each term is cut in half. Going from term to term it takes 35 hours each. The third term 226 is the result of waiting two half-lives, which is 2*35 = 70 hours that have elapsed total.

--------------

If you want to use a formula, then it would be

y = A*\left(\frac{1}{2}\right)^{x/H}

where,

H = half-life duration (in this case, it is 35)

A = starting amount (which is 904 in this case)

x = amount of time that has elapsed (we will plug in x = 70)

y = final amount after x units of time has elapsed

note that x and H must have the same time unit. Both are in terms of hours in this case.

------------

So we will plug A = 904, x = 70, H = 35 into the formula to get...

y = A*\left(\frac{1}{2}\right)^{x/H}\\\\y = 904*\left(\frac{1}{2}\right)^{70/35}\\\\y = 904*(0.5)^{2}\\\\y = 904*(0.25)\\\\y = 226\\\\

We see that x = 70 leads to y = 226. This means after 70 hours, there is 226 grams of the material left.

4 0
3 years ago
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