Answer: an epiphyseal line
Explaination: The epiphyseal plate is a zone of hyaline cartilage between the epiphysis and diaphysis of a long bone. When the cartilage is replaced with bone and the plate closes, the bone has reached its maximum length. This is called the epiphyseal line.
weight = mg acts
downwards <span>
normal force = N acts upwards.
and force F acts at an angle θ below the horizontal.
(Let us assume that the woman pushes from the left, so F is
acted towards the right, which is below the horizontal)
so that, Frictional force, f=us*N acts towards the left
Now we balance the forces along x and y directions:
y direction: N = mg + F sinΘ
x direction: us * N = F cosΘ
We let the value of µs be equal to a value such that any F
will not be able to move the crate. Then, if we increase F by an amount F',
then the force pushing the crate towards the right also increases by F' cosΘ. Additionally,
the frictional force f must raise by exactly this amount.
Since f can’t exceed us*N, so the normal force must increase
by F' cosΘ/us.
Also, from the y direction equation, the normal force exceeds
by F' sin Θ.
<span>These two values must be the same, therefore:
<span>us = cot θ</span></span></span>
Answer: The momentum is 500.
Explanation: The equation for momentum is p=mv, so you would multiply the mass of the player(50kg) and the speed of the ball(10m/s) to get 500.
Answer:
Fav = -12209 N
Explanation:
let p1 be the initial momentum of the ball and p2 be the final momentum of the ball. let v1 be the initial velocity of the ball and v2 be the final velocity of the ball.
From Newton's second law of motion, we get that the avarage force acting on the ball is given by:
Fav = Δp/t
= (p2 - p1)/t
= m(v2 - v1)/t
= [(145×10^-3)(-45.3 - 38.9)/(1×10^-3)
= - 12209 N
Therefore, the average force applies on the ball by tha bat is 12209 in the direction opposite to the balls initial direction.
