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Airida [17]
4 years ago
6

How can the density of an object be determined?”

Physics
2 answers:
Elanso [62]4 years ago
8 0

Answer:

m/p, aka mass/volume.

Explanation:

for example if you had an object that had a mass of 10 and volume of 5, the density of that object would be 10/5, or 2.

Nastasia [14]4 years ago
6 0

Answer:

First you need to know the mass (grams) of the object and its volume, then what you do is  Divide the mass by the volume in order to get an object's Density.

Explanation:

hope that helped good luck :)

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HURRY
motikmotik

Answer:

12

N

in the direction opposite to electric field.

Explanation:

Force on a charged particle

q

due to electric field

E

is given by

→

F

=

q

→

E

|

F

|

=

−

0.06

C

×

200

N

C

=

−

12 N

Here negative indicates that force is in the direction opposite to electric field.

6 0
2 years ago
What can one say for sure about element #99, Einsteinium (Es))? a) There's no such element! b) It is an alkali metal. c) It is r
Dmitrij [34]

Answer:

Option (C)

Explanation:

Einsteinium is an element of the periodic table grouped in the Actinide series, with atomic number 99. They are dense element and highly electro-positive. <u>They are highly radioactive</u>, i.e the atoms within the element are unstable and constantly decay until they reach a stable environment. It has 99 number of electrons and protons, 153 number of neutrons.

Due to its high radioactivity, they are health hazardous and can used in making nuclear weapons but their uses are very limited and unknown.

Thus, the correct answer is option (C).

8 0
4 years ago
True or false: Decreased output from the vasomotor center allows arterioles and veins to constrict.
wolverine [178]
<h3><u>Answer;</u></h3>

The above statement is False

<h3><u>Explanation;</u></h3>
  • Decreased output from the vasomotor center allows arterioles and veins to dilate.
  • The vasomotor center controls vessel tone or contraction of the smooth muscle in the tunica media.It is responsible for central regulation of cardiac electrical activity, myocardial performance, and peripheral vascular tone.
  • Changes in diameter affect peripheral resistance, pressure, and flow, which in turn affect cardiac output.
3 0
3 years ago
I need to know how to solve this problem for an upcoming exam
Nataly_w [17]
W=f*d = 5000N * 10 stories * each 4m  = 200 000 J
7 0
3 years ago
15 points. give me the method.
AveGali [126]

Answer:

\boxed{{160 \:  m(s)}^{ - 1} }

Explanation:

if \:the \:  frequencies \: are \to \\   f_{1} =  640Hz  \\ and \\f_{2}   = 480Hz \:  \\ but \:  \boxed{v = f \gamma }:   f =  \frac{v}{ \gamma } \\ if \:  \gamma_{1}  -  \gamma _{2}  = 1 =  \gamma  \\ f_{1}  - f_{2}  = 640 - 480 = \boxed{ 160Hz} = f \\ v = f \gamma = 160 \times 1 =  \boxed{{160 \:  m(s)}^{ - 1} }

5 0
3 years ago
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