(HELP PLEASEE) An object is 40.0 cm from a

Physics

1 answer:

PilotLPTM [1.2K]3 years ago

6 0

Answer:

-18

Explanation:

acellus use the formula of magnification and watch your minus sign

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a stone is dropped from top of a tower of 50m high ,simltaneously another stone is thrown upward with a speed of 20m/s find the

aleksklad [387]

At the time that I'll call ' Q ', the height of the stone that was
dropped from the tower is

   H = 50 - (1/2 G Q²) ,

and the height of the stone that was tossed straight up
from the ground is

   H = 20Q - (1/2 G Q²) .

The stones meet when them's heights are equal,
so that's the time when

   <span>50 - (1/2 G Q²) = 20Q - (1/2 G Q²) .

This is looking like it's going to be easy.

Add </span><span>(1/2 G Q²) to each side.
Then it says
       50 = 20Q

Divide each side by 20: 2.5 = Q .

And there we are. The stones pass each other

   2.5 seconds

after they are simultaneously launched.
</span>

5 0

3 years ago

Z. A force that gives a 8-kg objet an acceleration of 1.6 m/s^2 would give a 2-kg object an

Paladinen [302]

Answer:

$\boxed {\boxed {\sf D.\ 6.4\ m/s^2}}$

Explanation:

We need to find the acceleration of the 2 kilogram object. Let's complete this in 2 steps.

<h3>1. Force of 1st Object </h3>

First, we can find the force of the first, 8 kilogram object.

According to Newton's Second Law of Motion, force is the product of mass and acceleration.

$F=m \times a$

The mass of the object is 8 kilograms and the acceleration is 1.6 meters per square second.

m= 8 kg
a= 1.6 m/s²

Substitute these values into the formula.

$F= 8 \ kg * 1.6 \ m/s^2$

Multiply.

$F= 12.8 \ kg*m/s^2$

<h3>2. Acceleration of the 2nd Object </h3>

Now, use the force we just calculated to complete the second part of the problem. We use the same formula:

$F= m \times a$

This time, we know the force is 12.8 kilograms meters per square second and the mass is 2 kilograms.

F= 12.8 kg *m/s²
m= 2 kg

Substitute the values into the formula.

$12.8 \ kg*m/s^2= 2 \ kg *a$

Since we are solving for the acceleration, we must isolate the variable (a). It is being multiplied by 2 kg. The inverse of multiplication is division. Divide both sides of the equation by 2 kg.

$\frac {12.8 \ kg*m/s^2}{2 \ kg}= \frac{2\ kg* a}{2 \ kg}$