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vodomira [7]
3 years ago
12

A line has a slope of 2. Write an equation in slope intercept form for the line that is perpendicular to this line.

Mathematics
2 answers:
notsponge [240]3 years ago
6 0

Hey there!

A perpendicular line's slope to another line is always the negative reciprocal of slope.

If our line has a slope of two, we first must find the reciprocal, which is 1/2. Then, we put a negative on it.

Therefore, our equation is y=-1/2x+b.

I hope that this helps! Have a great day!

Elden [556K]3 years ago
6 0

Answer:

y=2x

Step-by-step explanation:

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Find the first three terms in the expansion , in ascending power of x , of (2+x)^6 and obtain the coefficient of x^2 in the expa
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The first 3 terms in the expansion of (2 + x)^{6} , in ascending power of x are,

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Step-by-step explanation:

(2+x)^{6}

= \sum_{k=0}^{6}(6_{C_{k}} \times x^{k} \times 2^{6 - k})

= 6_{C_{0}} \times x^{0} \times 2^{6}  + 6_{C_{1}} \times x^{1} \times 2^{5} + 6_{C_{2}} \times x^{2} \times 2^{4} + terms involving higher powers of x

= 64 + 192 \times x^{1} + 240 \times x^{2} + terms involving higher powers of x

so, the first 3 terms in the expansion of (2 + x)^{6} , in ascending power of x are,

64 , 192 \times x^{1} {\textrm{  and  }}240 \times x^{2}

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(2+x - x^{2})^{6}

= \sum_{k=0}^{6}(6_{C_{k}} \times (2 + x)^{k} \times (-x^{2})^{6 - k})

Now, by inspection,

the term x^{2} comes from k =5 and k = 6

for k = 5, the coefficient of  x^{2}  is , (-32) \times 6 = -192

for k = 6 , the coefficient of x^{2} is, 6_{C_{2}} \times 2^{4} = 240

so,   coefficient of x^{2} in the final expression = (240 - 192) = 48

3 0
3 years ago
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