3 years ago

En el triángulo de vértices: A(8,3) ,B(-6,5) y C(-2,-6), determine:

Mathematics

1 answer:

sergejj [24]3 years ago

6 0

Sí hola no speak espionage

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Reese wants to organize a party and decides to save money for it.He calculates that he needs $420 in 9 weeks.He already has $60

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Answer:

3840

Step-by-step explanation:

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How do i do this?.......

iris [78.8K]

Order of operations (from high priority to low priority):

Parentheses

Exponents

Multiplications/Division

Addition/Subtraction

All in left to right.

2 ÷ (5 + 3)⁻¹ ÷ 4

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5. Which polynomial is equal to (x5 + 1) divided by (x + 1)?

Mkey [24]

Answer:

B $x^4-x^3+x^2-x+1$

Step-by-step explanation:

Given,

Dividend = $(x^5+1)$

Divisor = $(x+1)$

Step 1: First The dividend is $(x^5+1)$ and Divisor is $(x+1)$ when divided first time the quotient will be $x^4$ and remainder will be $-x^4+1$

Step: 2 Now the new dividend is $-x^4+1$ and Divisor is $(x+1)$ when divided the quotient will be $x^4-x^3$ and remainder will be $x^3+1$

Step: 3 Now the new dividend is $x^3+1$ and Divisor is $(x+1)$ when divided the quotient will be $x^4-x^3+x^2$ and remainder will be $-x^2+1$

Step: 4 Now the new dividend is $-x^2+1$ and Divisor is $(x+1)$ when divided the quotient will be $x^4-x^3+x^2-x$ and remainder will be $x+1$

Step: 5 Now the new dividend is $x+1$ and Divisor is $(x+1)$ when divided the quotient will be $x^4-x^3+x^2-x+1$ and remainder will be 0.

Hence When the polynomial $(x^5+1)$ is divided by $(x+1)$ the answer or quotient will be equal to $x^4-x^3+x^2-x+1$ and remainder will be 0.

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3 years ago

Solve the following system of equations graphically.

fiasKO [112]

Step-by-step explanation:

work is shown and pictured

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