Using derivatives, it is found that the x-values in which the slope belong to the interval (-1,1) are in the following interval:
(-15,-10).
<h3>What is the slope of the tangent line to a function f(x) at point x = x0?</h3>
It is given by the derivative at x = x0, that is:
.
In this problem, the function is:
Hence the derivative is:
For a slope of -1, we have that:
0.4x + 5 = -1
0.4x = -6
x = -15.
For a slope of 1, we have that:
0.4x + 5 = 1.
0.4x = -4
x = -10
Hence the interval is:
(-15,-10).
More can be learned about derivatives and tangent lines at brainly.com/question/8174665
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GCF, Greatest Common Factor.
Answer:
124
Step-by-step explanation:
y = mx + b "m" is the slope, "b" is the y-intercept (the y value when x = 0)
1. slope: -3
y-intercept: 7
y = -3x + 7
Your answer is B
y + 3x = 7 Subtract 3x on both sides
y = -3x + 7
2. y + 9(x + 3) = 0 Multiply/distribute 9 into (x + 3)
y + 9x + 27 = 0 Subtract 9x and 27 on both sides to get "y" by itself
y = -9x - 27
slope: -9
y-intercept: -27 or (0,-27)
Your answer is D
3. Point-slope form: y - y₁ = m(x - x₁)
slope: -11
(x₁ , y₁) = (-5, 7)
y - 7 = -11(x - (-5)) The two negative signs becomes a positive
y - 7 = -11(x + 5)
Your answer is C
4. For this question, I think you get it from point-slope form to slope-intercept form (I'm not sure, but you still get the same answer if you just do slope-intercept form)
slope: -4
(x₁ , y₁) = (2, -8)
y - y₁ = m(x - x₁)
y - (-8) = -4(x - 2)
y + 8 = -4(x - 2) Multiply/distribute -4 into (x - 2)
y + 8 = -4x + 8 Subtract 8 on both sides to get "y" by itself
y = -4x
Your answer is A
Answer:
434
Step-by-step explanation:
29-20=9
20-11=9
9*47=423
423+11=434
