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Ede4ka [16]
3 years ago
5

Ms.Wright opens a savings account with a deposit of $800. The bank will pay her 3% interest per year A.) how much interest will

Ms.Wright receive at the end of 1/2 year B.) how much interest will she receive at the end of 1 year
Mathematics
1 answer:
Norma-Jean [14]3 years ago
3 0

A) Ms.Wright receive $12 as interest at the end of 1/2 year.

B)  Ms.Wright receive $24 as interest at the end of 1 year.

Step-by-step explanation:

The sum deposited in the bank = Principle  = $800

The rate of simple interest  = 3%

The time = 6 months  = (6/12) years   =  0.5 years

\textrm{SIMPLE INTEREST} =  \frac{P \times R \times t}{100} \\\implies SI  = \frac{800 \times 3 \times 0.5}{100}  = 12

So, here simple interest = $12.

So Ms.Wright receive $12 as interest at the end of 1/2 year.

B) Now here Time  = 1 year

so, Simple interest   = \frac{800 \times 3 \times1 }{100}  = 24

So Ms.Wright receive $24 as interest at the end of 1 year.

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dimulka [17.4K]

Answer:

a = \frac{g}{H+n}

Step-by-step explanation:

Step 1: Factor

g = a(H + n)

Step 2: Divide both sides by expression in parenthesis

g/(H + n) = a

7 0
3 years ago
Help evaluating the indefinite integral
Dafna11 [192]

Answer:

\displaystyle \int {\frac{x}{\sqrt{4 - x^2}}} \, dx = \boxed{ -\sqrt{4 - x^2} + C }

General Formulas and Concepts:
<u>Calculus</u>

Differentiation

  • Derivatives
  • Derivative Notation

Derivative Property [Multiplied Constant]:
\displaystyle (cu)' = cu'

Derivative Property [Addition/Subtraction]:
\displaystyle (u + v)' = u' + v'
Derivative Rule [Basic Power Rule]:

  1. f(x) = cxⁿ
  2. f’(x) = c·nxⁿ⁻¹

Integration

  • Integrals

Integration Rule [Reverse Power Rule]:
\displaystyle \int {x^n} \, dx = \frac{x^{n + 1}}{n + 1} + C

Integration Property [Multiplied Constant]:
\displaystyle \int {cf(x)} \, dx = c \int {f(x)} \, dx

Integration Methods: U-Substitution and U-Solve

Step-by-step explanation:

<u>Step 1: Define</u>

<em>Identify given.</em>

<em />\displaystyle \int {\frac{x}{\sqrt{4 - x^2}}} \, dx

<u>Step 2: Integrate Pt. 1</u>

<em>Identify variables for u-substitution/u-solve</em>.

  1. Set <em>u</em>:
    \displaystyle u = 4 - x^2
  2. [<em>u</em>] Differentiate [Derivative Rules and Properties]:
    \displaystyle du = -2x \ dx
  3. [<em>du</em>] Rewrite [U-Solve]:
    \displaystyle dx = \frac{-1}{2x} \ du

<u>Step 3: Integrate Pt. 2</u>

  1. [Integral] Apply U-Solve:
    \displaystyle \int {\frac{x}{\sqrt{4 - x^2}}} \, dx = \int {\frac{-x}{2x\sqrt{u}}} \, du
  2. [Integrand] Simplify:
    \displaystyle \int {\frac{x}{\sqrt{4 - x^2}}} \, dx = \int {\frac{-1}{2\sqrt{u}}} \, du
  3. [Integral] Rewrite [Integration Property - Multiplied Constant]:
    \displaystyle \int {\frac{x}{\sqrt{4 - x^2}}} \, dx = \frac{-1}{2} \int {\frac{1}{\sqrt{u}}} \, du
  4. [Integral] Apply Integration Rule [Reverse Power Rule]:
    \displaystyle \int {\frac{x}{\sqrt{4 - x^2}}} \, dx = -\sqrt{u} + C
  5. [<em>u</em>] Back-substitute:
    \displaystyle \int {\frac{x}{\sqrt{4 - x^2}}} \, dx = \boxed{ -\sqrt{4 - x^2} + C }

∴ we have used u-solve (u-substitution) to <em>find</em> the indefinite integral.

---

Learn more about integration: brainly.com/question/27746495

Learn more about Calculus: brainly.com/question/27746485

---

Topic: AP Calculus AB/BC (Calculus I/I + II)

Unit: Integration

5 0
2 years ago
The question is in the picture above. Please help
kow [346]

Answer:

it is 1

Step-by-step explanation:

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djyliett [7]
Here is your answer > >

Width of rectangle =15 inches

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We know that

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625=l^2+225

l^2=625-225

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l=Root 400

l=20 inches

Hope it helps!

Thankyou ☆ ☆

Bebrainly
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Vlad1618 [11]
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