Find two numbers a and b such that a+b=0 and ab=36
1 answer:
Answer:
b = 6i then a = -6i
b = -6i then a = 6i
Step-by-step explanation:
a+b=0
ab=36
a = -b
a(b) = 36
-b * b = 36
- b^2 = 36
b^2 = -36
Take the square root of each side
sqrt(b^2) = sqrt(-36)
b =± 6i
a = - (± 6i)
so b = 6i then a = -6i
b = -6i then a = 6i
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