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blagie [28]
4 years ago
11

Find two numbers a and b such that a+b=0 and ab=36

Mathematics
1 answer:
PolarNik [594]4 years ago
4 0

Answer:

b = 6i   then a = -6i

b = -6i   then a = 6i

Step-by-step explanation:

a+b=0

ab=36

a = -b

a(b) = 36

-b * b = 36

- b^2 = 36

b^2 = -36

Take the square root of each side

sqrt(b^2) = sqrt(-36)

b =± 6i

a = - (± 6i)

so b = 6i   then a = -6i

b = -6i   then a = 6i

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