Answer:
.
See the diagram attached below.
Let the chords be AB and AC with common point A.
AD is the diameter. Join B with D and C with D to form two triangles.
We need to prove that AB=AC.
\begin{gathered}In\ \triangle ABD\ and \triangle ACD;\\Given\ that\ \angle BAD=\angle CAD----(condition\ 1)\\since\ AD\ is\ diameter, \angle ABD=\angle ACD = 90^0\\So\ \angle ADB=\angle ADC--------(condition\ 2)\\AD=AD\ (common\ side)-----(condition\ 3)\\ \\So\ the\ triangles\ are\ congruent\ by\ ASA\ rule.\\Hence\ AB=AC.\end{gathered}
In △ABD and△ACD;
Given that ∠BAD=∠CAD−−−−(condition 1)
since AD is diameter,∠ABD=∠ACD=90
0
So ∠ADB=∠ADC−−−−−−−−(condition 2)
AD=AD (common side)−−−−−(condition 3)
So the triangles are congruent by ASA rule.
Hence AB=AC.
Answer:
x = 1
Step-by-step explanation:
We need to solve for x by isolating the variable.
First, expand the parentheses:
2(x + 1) = 4
2 * x + 2 * 1 = 4
2x + 2 = 4
Then subtract by 2:
2x + 2 - 2 = 4 - 2
2x = 2
Finally, divide by 2:
2x/2 = 2/2
x = 1
Thus, x = 1.
Hope this helps!
The probability that both of them go back to prison is 4.48%.
<h3>
What is probability?</h3>
- Probability is a measure of the likelihood of an event occurring.
- Many events cannot be predicted with total certainty.
- We can predict only the chance of an event to occur i.e., how likely they are going to happen, using it.
- The probability of an event is a number between 0 and 1, where, roughly speaking, 0 indicates the impossibility of the event and 1 indicates certainty.
The state recidivism rate is given by 22%.
So, the probability that both of the prisoners will go back to prison will be:
- = 22% × 22%
- = 0.22 × 0.22
- = 4.84%
Hence, the probability that both of them go back to prison is 4.48%.
To know more about probability, visit:
brainly.com/question/14975981
#SPJ9
Answer:
If my math is correct it should be $53.82
Step-by-step explanation:
You Divide 6.3kg by 0.35kg that would give you 18. Then you multiply $2.99 by 18 and that should get you $53.82
Step-by-step explanation:
<em>Given</em>
<em>We </em><em>know </em><em>that </em><em>in </em><em>a </em><em>parallelogram </em><em>opposite </em><em>angles </em><em>are </em><em>equal</em><em>. </em><em>So </em>
<em>1st </em><em>and </em><em>3rd </em><em>angles </em><em>=</em><em> </em><em>1</em><em>1</em><em>8</em><em>°</em>
<em>Let </em><em>2nd </em><em>and </em><em>4th </em><em>angles </em><em>=</em><em> </em><em>x</em>
<em>Now</em>
<em>1</em><em>1</em><em>8</em><em>°</em><em> </em><em>+</em><em> </em><em>1</em><em>1</em><em>8</em><em>°</em><em> </em><em>+</em><em> </em><em>x </em><em>+</em><em> </em><em>x </em><em>=</em><em> </em><em>3</em><em>6</em><em>0</em><em>°</em><em> </em><em>(</em><em> </em><em>Being </em><em>sum </em><em>of </em><em>angles </em><em>of </em><em>parallelogram</em><em>) </em>
<em>2</em><em>3</em><em>6</em><em>°</em><em> </em><em>+</em><em> </em><em>2x </em><em>=</em><em> </em><em>3</em><em>6</em><em>0</em><em>°</em>
<em>2x </em><em>=</em><em> </em><em>3</em><em>6</em><em>0</em><em>°</em><em> </em><em>-</em><em> </em><em>2</em><em>3</em><em>6</em><em>°</em>
<em>2x </em><em>=</em><em> </em><em>1</em><em>2</em><em>4</em><em>°</em>
<em>Therefore </em><em>x </em><em>=</em><em> </em><em>6</em><em>2</em><em>°</em>
<em>Now </em><em>the </em><em>measure </em><em>of </em><em>other </em><em>all </em><em>angles </em>
<em>118</em><em>°</em><em> </em><em>,</em><em> </em><em>6</em><em>2</em><em>°</em><em> </em><em>,</em><em> </em><em>1</em><em>1</em><em>8</em><em>°</em><em>,</em><em> </em><em>6</em><em>2</em><em>°</em>
