Answer:
(0,1) , (2,4) , (4,7)
Explanation:
convert the equation into slope-intercept form (this would be y=3/2x+1)
now plug in random numbers for x and solve for y by multiplying them by 3/2 and adding 1.
Complete Question
If $12000 is invested in an account in which the interest earned is continuously compounded at a rate of 2.5% for 3 years
Answer:
$ 12,934.61
Step-by-step explanation:
The formula for Compound Interest Compounded continuously is given as:
A = Pe^rt
A = Amount after t years
r = Interest rate = 2.5%
t = Time after t years = 3
P = Principal = Initial amount invested = $12,000
First, convert R percent to r a decimal
r = R/100
r = 2.5%/100
r = 0.025 per year,
Then, solve our equation for A
A = Pe^rt
A = 12,000 × e^(0.025 × 3)
A = $ 12,934.61
The total amount from compound interest on an original principal of $12,000.00 at a rate of 2.5% per year compounded continuously over 3 years is $ 12,934.61.
Answer:
![g(x)=-2\sqrt[3]x](https://tex.z-dn.net/?f=g%28x%29%3D-2%5Csqrt%5B3%5Dx)
or
Step-by-step explanation:
Given
![f(x) = \sqrt[3]x](https://tex.z-dn.net/?f=f%28x%29%20%3D%20%5Csqrt%5B3%5Dx)
Required
Write a rule for g(x)
See attachment for grid
From the attachment, we have:
We can represent g(x) as:
So, we have:
![g(x) = n * \sqrt[3]x](https://tex.z-dn.net/?f=g%28x%29%20%3D%20n%20%2A%20%5Csqrt%5B3%5Dx)
For:
![2 = n * \sqrt[3]{-1}](https://tex.z-dn.net/?f=2%20%3D%20n%20%2A%20%5Csqrt%5B3%5D%7B-1%7D)
This gives:
Solve for n
To confirm this value of n, we make use of:
So, we have:
![-2 = n * \sqrt[3]1](https://tex.z-dn.net/?f=-2%20%3D%20n%20%2A%20%5Csqrt%5B3%5D1)
This gives:
Solve for n
Hence:
or:
Isolate the x. Note the equal sign. What you do to one side you do to the other.
Subtract 2y from both sides
2x + 2y (-2y) = 10 (-2y)
2x = 10 - 2y
Isolate the x, divide 2 from both sides and from all terms.
(2x)/2 = (10 - 2y)/2
x = 5 - y
Place the variable in the front
x = -y + 5
x = -y + 5 is your answer
hope this helps
Answer: 53.333
Step-by-step explanation: you have to use the formula base times height divided by 3 please mark me the branliest
