1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
seropon [69]
3 years ago
5

Can someone please help me?

Mathematics
1 answer:
Alisiya [41]3 years ago
8 0

Answer:

Step-by-step explanation:

That composite figure is made up of a square and a quarter of a circle.  We will first find the area of the square.  Then we will find the area of the circle and divide it by 4.

Area of square = 1.6 × 1.6

Area of square = 2.56 m squared

Area of circle = (3.14)(1.6²) In case you forgot, the area of a circle is A = πr².

Area of circle = 8.0384

Divide that by 4 to get 2.0096.

Add 2.0096 to 2.56 to get the total area, which is

4.5696 or 4.6 rounded (choice D)

You might be interested in
Lowest common denominator of 3 5/7 and 4 4/5
IrinaK [193]

Answer: look at the screenshot

Step-by-step explanation:

it has everything you need

6 0
2 years ago
Multiply (2x + 2y)(2x + 2y)
Maslowich

Answer:

4x² + 4y² + 8xy

Step-by-step explanation:

( 2x + 2y ) ( 2x + 2y ) = ( 2x + 2y )²

Formula : -

( a + b )² = a² + b² + 2ab

Here,

a = 2x

b = 2y

( 2x + 2y )²

= ( 2x )² + ( 2y )² + 2 ( 2x ) ( 2y )

= 2²x² + 2²y² + 8xy

= 4x² + 4y² + 8xy

7 0
2 years ago
Read 2 more answers
Simplify: 27k^5m^8/(4k^3)(9m^2)
Yakvenalex [24]
The answer to your question is 3k^2m^6/4
4 0
2 years ago
What is the area of a square when the side length is 2/3cm
Leviafan [203]

\bf \textit{area of a square}\\\\ A=s^2~~ \begin{cases} s=length~of\\ \qquad a~side\\[-0.5em] \hrulefill\\ s=\frac{2}{3} \end{cases}\implies A=\left( \cfrac{2}{3} \right)^2\implies A=\cfrac{2^2}{3^2}\implies A=\cfrac{4}{9}

7 0
3 years ago
Find the area of the shaded region.
kolbaska11 [484]

Answer:

\boxed{ \tt\longrightarrow \: Area \:  Of  \: Shaded \:  region  \: =\boxed{ \tt 39  \: in²}}

Step-by-step explanation:

<u>Given:</u>

The Dimensions of Parallelogram are 12 in.(Base) and 7 in.(Height)

<em>And,</em>

The Dimensions of Rectangle are 9 in.(Length) and 5 in.(Breadth).

<u>To Find</u>:

The Area of Shaded region

<u>Solution:</u>

When the dimensions of parallelogram and the dimensions of rectangle are given, we need to find the Shaded region using this formula:

\boxed{\tt \longrightarrow Area  = (Parallelogram  - Rectangle)}

We know that the formula of Parallelogram is base*height[b×h] and the formula of rectangle is length*breadth[l*b] .

\tt\longrightarrow \: Area =B×h-l×b

Put their values accordingly:

\longrightarrow  \tt Area = (12 \times 7 - 9 \times 5)in {}^{2}

<u>Simplify it.</u>

<em>[</em><em>Follow BODMAS Rule strictly while </em><em>simplifying]</em>

\tt\longrightarrow \: Area = (84 - 45 ) in {}^{2}

\tt\longrightarrow \: Area = 39 \:  {in}^{2}

Hence, the Area of Shaded region would be 39 in² or 39 sq. in. .

\rule{225pt}{2pt}

I hope this helps!

8 0
2 years ago
Read 2 more answers
Other questions:
  • write the equation of the line that passes through the points (-4,4) and (6,9) and figure out what y=mx+b for this equation woul
    12·1 answer
  • If 5^3b-1 = 5^b-3 what is the value of b?
    14·1 answer
  • 2. An advertising firm has an old computer that can prepare a whole mailing in 6 hours. With
    11·1 answer
  • Please help me answer this i need asap
    9·1 answer
  • Given: Line segment WZ is congruent to line segment YZ. Line segment WX is parallel to line segment ZY
    13·2 answers
  • What is the surface area of a sphere with radius 2
    11·1 answer
  • 7thh grade math help me plzzzzzzz
    8·1 answer
  • On Monday, Abigail spent m minutes on her homework. On Tuesday, she spent 45 more minutes doing her homework than on Monday. On
    8·2 answers
  • Select each expression that is equivalent to 3/16 if x = 3/4
    7·1 answer
  • Factor the expression completely?<br><br>x^4-17x^2+72 ​
    14·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!