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3 years ago

Find the area of each sector.

Mathematics

1 answer:

sergey [27]3 years ago

5 0

Answer:

D. $\frac{525\pi}{8}$ m²

Step-by-step explanation:

Area of the sector = ½*r²∅

Where,

Radius (r) = 15 m

Angle in radians (∅) = $\frac{7\pi}{12}$

Plug in the values into the equation

Area of sector = $\frac{1}{2} * 15^2 * \frac{7\pi}{12}$

Area of sector = $\frac{1}{2} * 225 * \frac{7\pi}{12}$

Area of sector = $\frac{1*225*7\pi}{2*12}$

Area of sector = $\frac{1,575\pi}{24}$

Simplify

Area of sector = $\frac{525\pi}{8}$

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Keith_Richards [23]

Answer:

f(9) = 42

Step-by-step explanation:

f(9) = (-9)*2 + 5*9 +15

= -18 + 45 + 15

= 42

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4 years ago

Read 2 more answers

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maksim [4K]

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3 years ago

Here are the graphs of L(x) and R(x) what are the values of L(2) and R(2)

Sedaia [141]

Using the function graph given, it is found that:

L(2) = 7.

R(2) = 1.

When a piece-wise function is given, that is, a function that has multiple definitions, the numeric value at x when the definition changes is given by the closed circle.

For function L(x), when x = 2, the closed circle is at y = 7, hence, L(2) = 7.

For function R(x), when x = 2, the closed circle is at y = 1, hence, R(2) = 1.

To learn more about the use of graphs to analyze a function, you can take a look at brainly.com/question/21447009

3 0

2 years ago

Find p(0),p(1),p(-1) and p(2) of the 3x(x-2)

Effectus [21]

Answer:

make x→0

$p(0)=(0)^{2}-3(0)+2$

→ $p(0)=0+0+2$

→ $p(0)=2$

$------$

Replace x→-1

$p(-1)=(-1) ^{2} -3 (-1)+2$

→ $p(-1)=1-3+2$

→ $p(-1)=0$

$----------$

Now make x→2

$p(2)=(2) ^{2} -3(2)+2$

→ $p(2)=4-6+2$

→ $p(2)=0$

$Answer:-2,0,0$

$-----------$

hope it helps...

have a great day!!

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3 years ago

-5y - 6bStep 1 of 2: Identify the first term of the algebraic expression. Indicate whether theterm is a variable term or a const

ira [324]

Answer:

a. Variable term

b. Variable term

Explanation:

a) We were given the algebraic expression:

$-5y-6b$

The first term of the algebraic expression is:

$-5y$

The first term is a variable term

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b) We were given the algebraic expression:

$-5y-6b$

The second term of the algebraic expression is:

$-6b$

The second term is a variable term

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6 0

1 year ago