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Alexxandr [17]
3 years ago
14

Find the area of each sector.

Mathematics
1 answer:
sergey [27]3 years ago
5 0

Answer:

D. \frac{525\pi}{8} m²

Step-by-step explanation:

Area of the sector = ½*r²∅

Where,

Radius (r) = 15 m

Angle in radians (∅) = \frac{7\pi}{12}

Plug in the values into the equation

Area of sector = \frac{1}{2} * 15^2 * \frac{7\pi}{12}

Area of sector = \frac{1}{2} * 225 * \frac{7\pi}{12}

Area of sector = \frac{1*225*7\pi}{2*12}

Area of sector = \frac{1,575\pi}{24}

Simplify

Area of sector = \frac{525\pi}{8}

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I’m not sure of how to do this. Pls help
Semmy [17]
Just divide. 3/4 is 3 divided by 4= .75
75 hundredths is the same as 75%
20/100 20 divided by 100=.20 which is 20%
14 divided by 25 is .56, or 56%
1/5 is 1 divided by 5 = .20 or 20 %
3 0
3 years ago
An illusionist needs up to 10 volunteers for a show. She needs no fewer than 4 female volunteers. Let x represent the number of
Sliva [168]

The <em><u>correct answers</u></em> are:

B- x + y ≤ 10 ; and D- x ≥ 4

Explanation:

The illusionist needs at least 4 female volunteers.  This means he could use 4 or more; this means x, the number of female volunteers, is greater than or equal to 4:

x ≥ 4

The total of number of volunteers needed is up to 10.  This means the illusionist can use 10 or fewer people; this means the total is less than or equal to 10.

The number of female volunteers is x and the number of male volunteers is y; together they create the expression x+y.  This gives us

x+y ≤ 10

7 0
3 years ago
Read 2 more answers
Use the law of cosines to find the length of a
borishaifa [10]

Answer:

Step-by-step explanation:

You don't need the Law of Cosines, the Law of sines if what you need. You can't use the Law of Cosines because in order to find side a, you would need the length of side c and you don't have it. Using the Law of Sines is appropriate, knowing that angle B = 55:

\frac{sin55}{175}=\frac{sin42}{a} and solving for a:

a=\frac{175sin42}{sin55} so

a = 143.0

4 0
2 years ago
A ribbon is cut into n parts. The length of each part increases such that they form a geometric progression. SPM Given the lengt
emmainna [20.7K]

Answer:

Step-by-step explanation:

Let\ say\ r \ the \common\ ratio:\\a)a_4=r^2*a_2=9*a_2\Longrightarrow\ r=3\ (not\ -3\ since\ parts\ are\ positive)\\\\b)\\\displaystyle \sum_{i=1}^{n} a_i =a_1+a_2+a_3+...+a_n\\\\=a_1+a_1*r+a_1*r^2+a_1*r^3+...+a_1*r^{n-1}\\\\=a_1*(1+r+r^2+...+r^{n-1})\\\\=a_1*\dfrac{r^n-1}{r-1} \\\\147620=5*\frac{(3^n-1)}{3-1} \\\\3^n-1=\frac{2*147620}{5} \\\\3^n=59049 \\\\n*ln(3)=ln(59049)\\\\n=\dfrac{ln(59049)}{ln(3)} \\\\n=10\\\\a_n=5*3^{10-1}=5*19683=98415(cm)

5 0
2 years ago
Point 6,8 lies in which quadrant
OverLord2011 [107]

Answer:

Quadrant one if its positive (6, 8)

3 0
2 years ago
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