The answer to the question is 64°
x° + 26°= 90°
x° = 64°
15/35 of her attempts were successful.
Answer:
m∠JKP = 31.5°
Step-by-step explanation:
Incenter of a triangle is the point where all the bisectors of interior angles intersect each other.
JN is the angle bisector of ∠KJL.
Therefore, m∠KJN = m∠LJN
(7x - 6) = (5x + 4)
7x - 5x = 6 + 4
2x = 10
x = 5
m∠KJN = (7x - 6)
= 7(5) - 6
= 35 - 6
= 29°
In ΔKJN,
m∠JKN + m∠KNJ + m∠NJK = 180°
m∠JKN + 90° + 29° = 180°
m∠JKN = 180°- 119° = 61°
Since KO is the angle bisector of ∠JKN,
m∠JKP = 
= 
= 30.5°
To find the volume of the box you will use the volume of the sphere formula to find the radius of the circular region of the sphere. You wil then double the radius to find the diameter.
V = 4/3 x pi x r^3
972 x pi= 4/3 x pi x r^3
729 = r^3
The cubic root of 729 is 9 because 9 x 9 x 9 = 729.
The radius is 9 inches, and the diameter is 18 inches.
The volume of the box is 18 in x 18 in x 18 in or 5832 in.³.