Answer:
Sharla, 4400
Step-by-step explanation:
Paul's Salary:
Paul started at company B. Starting salary of company B is $ 28,000 with a yearly increase of $ 2,400. Paul's Salary in first year will be 28,000. In second year his salary will be 28000 + 2400, in 3rd year his salary will be: 28000 + 2(2400) and so on.
Since, the increase in Paul's salary every year is $ 2400, the increase in his salary after 10 years or in 10th year would be = 2400 x 9 = $ 21,600
So, his total salary in 10th year would be = 28000 + 21600 = $ 49,600
Sharla's Salary:
Sharla started at company C. Starting salary of company C is $ 36,000 with a yearly increase of $ 2,000.
Since, the increase in Sharla's salary every year is $ 2000, the increase in her salary after 10 years or in 10th year would be = 2000 x 9 = $ 18,000
So, her total salary in 10th year would be = 36000 + 18000 = $ 54,000
Conclusion:
Sharla earned more in 10th year an amount equal to $ 4400. So the answer is:
In the last year, <u>Sharla</u> earned <u>$4,400</u> more.
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