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2 years ago

You bought a sandwich for 12.40 it includes the tax 5% what is the cost of the sandwich before tax?

Mathematics

1 answer:

s344n2d4d5 [400]2 years ago

8 0

Answer: $11.81✔️cost of the sandwich before tax

Step-by-step explanation:

Let C = cost before tax

Cell phone costs = C + C·5% = $12.40

C(1 + 0.05) = $12.40

C = $12.40/1.05 = $11.81 , cost before tax

Answer: $11.81✔️ cost of the sandwich before tax

<h3>Checking</h3>

Cell phone after tax = $11.81 + $11.81·5/100

Cell phone after tax = $11.81 + $0.59 = $12.40✔️checked!

<h2><em>Spymore </em></h2>

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Suppose X, Y, and Z are random variables with the joint density function f(x, y, z) = Ce−(0.5x + 0.2y + 0.1z) if x ≥ 0, y ≥ 0, z

dexar [7]

Answer:

The value of the constant C is 0.01 .

Step-by-step explanation:

Given:

Suppose X, Y, and Z are random variables with the joint density function,

$f(x,y,z) = \left \{ {{Ce^{-(0.5x + 0.2y + 0.1z)}; x,y,z\geq0 } \atop {0}; Otherwise} \right.$

The value of constant C can be obtained as:

$\int_x( {\int_y( {\int_z {f(x,y,z)} \, dz }) \, dy }) \, dx = 1$

$\int\limits^\infty_0 ({\int\limits^\infty_0 ({\int\limits^\infty_0 {Ce^{-(0.5x + 0.2y + 0.1z)} } \, dz }) \, dy } )\, dx = 1$

$C\int\limits^\infty_0 {e^{-0.5x}(\int\limits^\infty_0 {e^{-0.2y }(\int\limits^\infty_0 {e^{-0.1z} } \, dz }) \, dy }) \, dx = 1$

$C\int\limits^\infty_0 {e^{-0.5x}(\int\limits^\infty_0{e^{-0.2y}([\frac{-e^{-0.1z} }{0.1} ]\limits^\infty__0 }) \, dy }) \, dx = 1$

$C\int\limits^\infty_0 {e^{-0.5x}(\int\limits^\infty_0 {e^{-0.2y}([\frac{-e^{-0.1(\infty)} }{0.1}+\frac{e^{-0.1(0)} }{0.1} ]) } \, dy }) \, dx = 1$

$C\int\limits^\infty_0 {e^{-0.5x}(\int\limits^\infty_0 {e^{-0.2y}[0+\frac{1}{0.1}] } \, dy }) \, dx =1$

$10C\int\limits^\infty_0 {e^{-0.5x}([\frac{-e^{-0.2y} }{0.2}]^\infty__0 }) \, dx = 1$

$10C\int\limits^\infty_0 {e^{-0.5x}([\frac{-e^{-0.2(\infty)} }{0.2}+\frac{e^{-0.2(0)} }{0.2}] } \, dx = 1$

$10C\int\limits^\infty_0 {e^{-0.5x}[0+\frac{1}{0.2}] } \, dx = 1$

$50C([\frac{-e^{-0.5x} }{0.5}]^\infty__0}) = 1$

$50C[\frac{-e^{-0.5(\infty)} }{0.5} + \frac{-0.5(0)}{0.5}] =1$

$50C[0+\frac{1}{0.5} ] =1$

$100C = 1$ ⇒ $C = \frac{1}{100}$

C = 0.01

3 0

2 years ago

Where are the black dots located at ?!!

butalik [34]

Answer:

(1,-2) and (6, 3)

Step-by-step explanation:

Hope this helps ^-^

4 0

2 years ago

Read 2 more answers

The question is there

Katarina [22]

Answer:

3 cm

Step-by-step explanation:

Set up an equation that solves for the surface area, "112 $cm^{2}$ " :

10(2)+10(2)+2x+2x+10x+10x = 112

20+20+4x+20x = 112

24x+40=112

24x=72

x=3

So, 3 cm.

7 0

2 years ago

What is the average speed for the interval t=1 hour to t=3 hours

inysia [295]

Answer:

7.5 miles per hour

Step-by-step explanation:

Average speed over the interval [1, 3] = (distance at 3 hrs -distance at 1 hr)/(3 hrs - 1 hr)

From the graph:

Distance at 3 hrs = 30 => (3, 30)

Distance at 1 hr = 15 => (1, 15)

Average speed = (30 - 15)/(3 - 1)

Average speed = 15/2

= 7.5

Therefore, average speed = 7.5 miles per hour

5 0

2 years ago

PLZ help me i will give you ten points for it and for helping me on the rest of the 6 problems PLZ HELP!!

Helen [10]

<u>Answer:</u>

Yes, I believe so.

<u>Step-by-step explanation:</u>

When you look at this equation on a graphing table, it is a straight line that goes directly through the 0,0 cords.

I hope this helped!

If it's wrong I'm very sorry!

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2 years ago