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3 years ago

mark wants to order a pizza. which is the better deal 10.00 with a diameter of 12 or 20.00 with a diameter of 18

1 answer:

7 0

I'm gonna calculate by the area of pizza to see how much food you get for 10 and 20 dollars

A...area
r...radius
d...diameter

d1=12 r1=6
d2=18 r2=9

A1=r1^2×3.14
A1=6^2×3.14
A1=36×3.14
A1=113.04

A2=r2^2×3.13
A2=9^2×3.14
A2=81×3.14
A2=254.34

if you bought 2, 12 diameter pizzas for 20 dollars you would get 226.08 area od food,still less if you bought 1, 18 diameter pizza for 20 dollars. because 223.08 < 254.34

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(06.04 MC) Dennis drew the line of best fit on the scatter plot shown below: What is the approximate equation of this line of be

elena-14-01-66 [18.8K]

Answer:

Step-by-step explanation:

In order to write the equation of this line, we need to pick 2 points on the graph where the line goes right through the intersection of the grids. Actually, you only need 1 of these, because the line goes through at (0, 15). Another point then can be (6, 6). Locate this point so you know what I means when I say that the line goes right through where the grids intersect at x = 6 and y = 6 (as opposed to somewhere in the middle of one of these grids). Find the slope between these 2 points:

$m=\frac{6-15}{6-0}=-\frac{9}{6}=-\frac{3}{2}$

Since there's only one choice with that slope, that is the choice you want.

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3 years ago

This recipe makes 7 portions of chocolate mousse.

Artist 52 [7]

Answer

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_____________________________

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3 years ago

In a random sample of 25 people, the mean commute time to work was 33.9 minutes and the standard deviation was 7.2 minutes. Ass

Phoenix [80]

Answer:

$33.9-1.32\frac{7.2}{\sqrt{25}}=31.999$

$33.9+1.32\frac{7.2}{\sqrt{25}}=35.801$

So on this case the 80% confidence interval would be given by (31.999;35.801)

And the margin of error is given by:

$ME = t_{\alpha/2}\frac{s}{\sqrt{n}}$

And replacing we got:

$ME = 1.32\frac{7.2}{\sqrt{25}} =1.9008$

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

$\bar X=33.9$ represent the sample mean for the sample

$\mu$ population mean (variable of interest)

s=7.2 represent the sample standard deviation

n=25 represent the sample size

Solution to the problem

The confidence interval for the mean is given by the following formula:

$\bar X \pm t_{\alpha/2}\frac{s}{\sqrt{n}}$ (1)

In order to calculate the critical value $t_{\alpha/2}$ we need to find first the degrees of freedom, given by:

$df=n-1=25-1=24$

Since the Confidence is 0.80 or 80%, the value of $\alpha=0.2$ and $\alpha/2 =0.1$ , and we can use excel, a calculator or a table to find the critical value. The excel command would be: "=-T.INV(0.01,24)".And we see that $t_{\alpha/2}=1.32$