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Roman55 [17]
2 years ago
12

That answer is wrong it is ether $0.80, $0.60, or $1.00

Mathematics
1 answer:
lana [24]2 years ago
5 0

Answer:

Expose. Robert

Step-by-step explanation:

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How to add and subtract positive and negative numbers?
mina [271]
Negative and negative equals a positive and positive and a negative equals a negative and then positive and positive equals positive hopefully that helped

4 0
3 years ago
Find the first four terms of the sequence given by the following.<br> aₙ=43-3(n-1) n=1,2,3. . .
Serggg [28]

Given :-

  • The general term of a sequence is given by aₙ=43-3(n-1) .

To Find :-

  • The first four terms of the sequence.

Solution :-

The given expression is /

→ aₙ=43-3(n-1)

where n > 0

<u>Finding</u><u> the</u><u> </u><u>first </u><u>term </u><u>:</u>

Substituting n = 1 , we have ,

→ T1 = 43 - 3(1-1)

→ T1 = 43 - 3*0

→ T1 = 43 - 0 = 43

<u>Finding</u><u> the</u><u> </u><u>second</u><u> </u><u>term </u><u>:</u>

Substituting n = 2 , we have,

→ T2 = 43 -3(2-1)

→ T2 = 43 -3*1

→ T2 = 43 -3 = 40

<u>Finding</u><u> </u><u>the </u><u>third </u><u>term</u><u> </u><u>:</u>

Substituting n = 3 , we have,

→ T3 = 43 -3(3-1)

→ T3 = 43 -3*2

→ T3 = 43 -6 = 37

<u>Finding</u><u> the</u><u> </u><u>fourth</u><u> </u><u>term </u><u>:</u>

→ T4 = 43 -3(4-1)

→ T4 = 43 -3*3

→ T4 = 43-9 = 34

<u>Hence</u><u> the</u><u> </u><u>first</u><u> </u><u>four</u><u> terms</u><u> of</u><u> </u><u>the</u><u> </u><u>sequence</u><u> </u><u>are </u><u>4</u><u>3</u><u> </u><u>,</u><u> </u><u>4</u><u>0</u><u> </u><u>,</u><u> </u><u>37</u><u> </u><u>and </u><u>34</u><u> </u><u>.</u>

<em>I </em><em>hope</em><em> this</em><em> helps</em><em> </em><em>.</em><em> </em><em>Let </em><em>me</em><em> know</em><em> if</em><em> you</em><em> </em><em>need </em><em>further</em><em> </em><em>clarification</em><em> </em><em>.</em>

7 0
2 years ago
You borrowed $25 from your friend. You paid him back in full after 6 months. He charged $2 for interest. What was the annual sim
Paraphin [41]
\bf \qquad \textit{Simple Interest Earned}\\\\&#10;I = Prt\qquad &#10;\begin{cases}&#10;I=\textit{interest earned}\to &\$2\\&#10;P=\textit{original amount}\to& \$25\\&#10;r=rate \\&#10;t=years\to &\frac{1}{2}&#10;\end{cases}

bearing in mind, "t" is in years, 6months is just 1/2 year

solve for "r", you'd get a decimal amount, multiply times 100, to get the percentage form
5 0
3 years ago
Read 2 more answers
Solve the following system
scZoUnD [109]

Answer:

{x = -4 , y = 2 ,  z = 1

Step-by-step explanation:

Solve the following system:

{-2 x + y + 2 z = 12 | (equation 1)

2 x - 4 y + z = -15 | (equation 2)

y + 4 z = 6 | (equation 3)

Add equation 1 to equation 2:

{-(2 x) + y + 2 z = 12 | (equation 1)

0 x - 3 y + 3 z = -3 | (equation 2)

0 x+y + 4 z = 6 | (equation 3)

Divide equation 2 by 3:

{-(2 x) + y + 2 z = 12 | (equation 1)

0 x - y + z = -1 | (equation 2)

0 x+y + 4 z = 6 | (equation 3)

Add equation 2 to equation 3:

{-(2 x) + y + 2 z = 12 | (equation 1)

0 x - y + z = -1 | (equation 2)

0 x+0 y+5 z = 5 | (equation 3)

Divide equation 3 by 5:

{-(2 x) + y + 2 z = 12 | (equation 1)

0 x - y + z = -1 | (equation 2)

0 x+0 y+z = 1 | (equation 3)

Subtract equation 3 from equation 2:

{-(2 x) + y + 2 z = 12 | (equation 1)

0 x - y+0 z = -2 | (equation 2)

0 x+0 y+z = 1 | (equation 3)

Multiply equation 2 by -1:

{-(2 x) + y + 2 z = 12 | (equation 1)

0 x+y+0 z = 2 | (equation 2)

0 x+0 y+z = 1 | (equation 3)

Subtract equation 2 from equation 1:

{-(2 x) + 0 y+2 z = 10 | (equation 1)

0 x+y+0 z = 2 | (equation 2)

0 x+0 y+z = 1 | (equation 3)

Subtract 2 × (equation 3) from equation 1:

{-(2 x)+0 y+0 z = 8 | (equation 1)

0 x+y+0 z = 2 | (equation 2)

0 x+0 y+z = 1 | (equation 3)

Divide equation 1 by -2:

{x+0 y+0 z = -4 | (equation 1)

0 x+y+0 z = 2 | (equation 2)

0 x+0 y+z = 1 | (equation 3)

Collect results:

Answer:  {x = -4 , y = 2 ,  z = 1

4 0
3 years ago
Find x for,<br> sin⁻¹ 4x + sin⁻¹ 3x = -<img src="https://tex.z-dn.net/?f=%5Cfrac%7B%5Cpi%20%7D%7B2%7D" id="TexFormula1" title="\
Novay_Z [31]
<h2>Explanation:</h2><h2></h2>

Let's solve this problem graphically. Here we have the following equation:

sin^{-1}(4x) + sin^{-1}(3x) = -\frac{\pi}{2}

So we can rewrite this as:

f(x)=sin^{-1}(4x) + sin^{-1}(3x) \\ \\ g(x)= -\frac{\pi}{2}

So the solution to the equation is the x-value at which the functions f and g intersect. In other words:

f(x)=g(x) \\ \\ sin^{-1}(4x) + sin^{-1}(3x) = -\frac{\pi}{2}

Using graphing calculator, we get that this value occurs at:

\boxed{x=-0.2}

3 0
3 years ago
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