Let x be the number of minutes Peg and Larry used their phones. So their costs can be written as:
Cost of Peg's Phone usage = 25 + 0.25x
Cost of Larry's Phone usage = 35 + 0.20x
We are to find when the Peg's phone will be more than Larry's phone. We can set up the inequality as:
25 + 0.25x > 35 + 0.20x
Re-arranging the inequality
0.25x - 0.20x > 35 - 25
0.05x > 10
x > 10/0.05
x > 200
Thus, Pag's phone will cost more if the number of minutes of phone usage is more than 200
2x+5y=619
x=10y-3
________
2(10y-3) +5y=619
20y-6+5y=619
25y=619+6
25y=625
y=625/25
y=25
x=10*25-3
x=250-3
x=247
Log (7/4) is equivalent to log (7.7/4.4), therefore it's log(7.7) - log(4.4), or...
2.0142 - 1.4816 = 0.5326
Answer:
see below
Step-by-step explanation:
10/5
(10 over five)
Which is 2
60x9=540 I believe is the answer
