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3 years ago

-2(3y - 6) + 4(5y - 8) = 92

Mathematics

2 answers:

Whitepunk [10]3 years ago

3 0

Answer:

y = 8

Step-by-step explanation:

$-2(3y - 6) + 4(5y - 8) = 92\\\\\mathrm{Expand\:}-2\left(3y-6\right)+4\left(5y-8\right):\quad 14y-20\\14y-20=92\\\\\mathrm{Add\:}20\mathrm{\:to\:both\:sides}\\14y-20+20=92+20\\\\Simplify\\14y=112\\\\\mathrm{Divide\:both\:sides\:by\:}14\\\frac{14y}{14}=\frac{112}{14}\\\\Simplify\\y= 8$

zepelin [54]3 years ago

3 0

Answer:

Step-by-step explanation:

-6y + 12 + 20y - 32 = 92

14y -20 = 92

14y = 112

y = 8

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Answer:

9/2

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Step-by-step explanation:

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3 years ago

A Baker used 7 bags of cookie-doe to make 10 cookies he used__ of a doe for each cookies- How many?

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2 years ago

Read 2 more answers

PLZ NEED HELP ASAP SHOW WORK TO PLZ IT WOULD MEAN A LOT

Marizza181 [45]

First Chart: Perimeter

Square Portion:

Original Side Lengths: P = 4 (1 + 1 + 1 + 1 ) =4

Double Side Lengths: P = 8 (2 x 4 = 8)

Triple Side Lengths: P = 12 (4 x 3 = 12)

Quadruple Side Lengths: P = 16 (4 x 4 = 16)

Rectangle Portion:

Original Side Lengths: P = 6 (1 x 2 + 2 x 2 = 6)

Double Side Lengths: P = 12 (2 x 2 + 4 x 2 = 12)

Triple Side Lengths: P = 24 (4 x 2 + 8 x 2 = 24)

Quadruple Side Lengths: P = 48 (8 x 2 + 16 x 2 = 48)

Second Chart: Area

Square Portion:

Original Side Lengths: A = 1 (1 x 1 = 1)

Double Side Lengths: A = 4 (2 x 2 = 4)

Triple Side Lengths: A = 9 (3 x 3 = 9

Quadruple Side Lengths: A = 16 ( 4 x 4 = 16)

Rectangle Portion:

Original Side Lengths: A = 2 ( 1 x 2 = 2 )

Double Side Lengths: A = 8 ( 2 x 4 = 8)

Triple Side Lengths: A = 18 ( 3 x 6 = 18)

Quadruple Side Lengths: A = 32 (4 x 8 = 32)

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2 years ago

Verify the Identity

valina [46]

Answer:

Cos x sec^2 x

Cos x (1 + cot x)

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Step-by-step explanation:

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3 years ago

A flat circular plate has the shape of the region x squared plus y squared less than or equals 1.The plate, including the bound

rjkz [21]

Answer:

We have the coldest value of temperature $T(\frac{3}{4},0) = -9/16$ . and the hottest value is $T(-(3/4),\frac{\sqrt{7}}{4})=\frac{5}{16}$ .

Step-by-step explanation:

We need to take the derivative with respect of x and y, and equal to zero to find the local minimums.

The temperature equation is:

$T(x,y)=x^{2}+2y^{2}-\frac{3}{2}x$

Let's take the partials derivatives.

$T_{x}(x,y)=2x-\frac{3}{2}=0$

$T_{y}(x,y)=4y=0$

So, we can find the critical point (x,y) of T(x,y).

$2x-\frac{3}{2}=0$

$x=\frac{3}{4}$

$4y=0$

$y=0$

The critical point is (3/4,0) so the temperature at this point is: $T(\frac{3}{4},0)=(\frac{3}{4})^{2}+2(0)^{2}-(\frac{3}{2})(\frac{3}{4})$

$T(\frac{3}{4},0)=-\frac{9}{16}$

Now, we need to evaluate the boundary condition.

$x^{2}+y^{2}=1$

We can solve this equation for y and evaluate this value in the temperature.

$y=\pm \sqrt{1-x^{2}}$

$T(x,\sqrt{1-x^{2}})=x^{2}+2(1-x^{2})-\frac{3}{2}x$

$T(x,\sqrt{1-x^{2}})=-x^{2}-\frac{3}{2}x+2$

Now, let's find the critical point again, as we did above.

$T_{x}(x,\sqrt{1-x^{2}})=-2x-\frac{3}{2}=0$

$x=-\frac{3}{4}$

Evaluating T(x,y) at this point, we have:

$T(-(3/4),\sqrt{1-(-3/4)^{2}})=-(-\frac{3}{4})^{2}-\frac{3}{2}(-\frac{3}{4})+2$

$T(-(3/4),\frac{\sqrt{7}}{4})=\frac{5}{16}$

Now, we can see that at point (3/4,0) we have the coldest value of temperature $T(\frac{3}{4},0) = -9/16$ . On the other hand, at the point $-(3/4),\frac{\sqrt{7}}{4})$ we have the hottest value of temperature, it is $T(-(3/4),\frac{\sqrt{7}}{4})=\frac{5}{16}$ .

I hope it helps you!

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2 years ago