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Katarina [22]
3 years ago
9

You draw two cards from a standard deck of 52 cards. What is the probability of drawing a face card and then an ace consecutivel

y from the deck without replacement?
Mathematics
2 answers:
lozanna [386]3 years ago
7 0

Answer:

\frac{4}{221}\approx 0.0181.

Step-by-step explanation:

We have been given that you draw two cards from a standard deck of 52 cards. We are asked to find the probability of drawing a face card and then an ace consecutively from the deck without replacement.

We know that a standard deck contains 12 face cards.

So probability of drawing a face card would be number of face cards over total cards.

\text{P(Face card})=\frac{12}{52}

\text{P(Face card})=\frac{3}{13}

We know that there are 4 aces is a standard deck.

Since we are not not replacing cards, so total number of cards after 1st draw would be 51 cards.

\text{P(Ace})=\frac{4}{51}

Probability of drawing a face card and then an ace consecutively from the deck without replacement would be product of both probabilities.

\text{P(Face card and Ace})=\frac{3}{13}\times \frac{4}{51}

\text{P(Face card and Ace})=\frac{1}{13}\times \frac{4}{17}

\text{P(Face card and Ace})=\frac{4}{221}

Therefore, the probability of drawing a face card and then an ace consecutively from the deck without replacement is \frac{4}{221}\approx 0.0181.

liberstina [14]3 years ago
7 0

Answer:

4/221

Step-by-step explanation:

  • USA Test Prep ! <3
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Answer:

There should be 18 blue marbles in the representative sample.

Step-by-step explanation:

Given that a bag contains 9 white and 54 blue marbles, if a representative sample contains 3 white marbles, to determine how many blue marbles would you expect to contain the following calculation must be performed:

9 = 3

54 = X

54 x 3/9 = X

162/9 = X

18 = X

Therefore, there should be 18 blue marbles in the representative sample.

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Step-by-step explanation:

12•13.5=162

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Step-by-step explanation:

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Which statement describes the inverse of m(x) = x2 – 17x?
stealth61 [152]

Answer:

The correct option is;

The \ domain \ restriction \ x \geq \dfrac{17}{2} \ results \ in \ m^{-1}(x) = \dfrac{17}{2} \pm \sqrt{x + \dfrac{289}{4} }}

Step-by-step explanation:

The given information is that m(x) = x² - 17·x

The above equation can be written in the form;

y = x² - 17·x

Therefore;

0 = x² - 17·x - y

From the general solution of a quadratic equation, 0 = a·x² + b·x + c we have;

x = \dfrac{-b\pm \sqrt{b^{2}-4\cdot a\cdot c}}{2\cdot a}

By comparison to the equation,0 = x² - 17·x - y, we have;

a = 1, b = -17, and c = -y

Substituting the values of a, b and c into the formula for the general solution of a quadratic equation, we have;

x = \dfrac{-(-17)\pm \sqrt{(-17)^{2}-4\times (1) \times (-y)}}{2\times (1)} = \dfrac{17\pm \sqrt{289+4\cdot y}}{2}

Which can be simplified as follows;

x =  \dfrac{17\pm \sqrt{289+4\cdot y}}{2}= \dfrac{17}{2} \pm \dfrac{1}{2}  \times \sqrt{289+4\cdot y}} = \dfrac{17}{2} \pm \sqrt{\dfrac{289}{4} +\dfrac{4\cdot y}{4} }}

And further simplified as follows;

x = \dfrac{17}{2} \pm \sqrt{\dfrac{289}{4} +y }} = \dfrac{17}{2} \pm \sqrt{y + \dfrac{289}{4} }}

Interchanging x and y in the function of the inverse, m⁻¹(x), we have;

m^{-1}(x) = \dfrac{17}{2} \pm \sqrt{x + \dfrac{289}{4} }}

We note that the maximum or minimum point of the function, m(x) = x² - 17·x found by differentiating the function and equating the result to zero, gives;

m'(x) = 2·x - 17 = 0

x = 17/2

Similarly, the second derivative is taken to determine if the given point is a maximum or minimum point as follows;

m''(x) = 2 > 0, therefore, the point is a minimum point on the graph

Therefore, as x increases past the minimum point of 17/2, m⁻¹(x) increases to give;

The \ domain \ restriction \ x \geq \dfrac{17}{2} \ results \ in \ m^{-1}(x) = \dfrac{17}{2} \pm \sqrt{x + \dfrac{289}{4} }} to increase m⁻¹(x) above the minimum.

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