7=x^2+20x+82
0=x^2+20x+75
What adds to 20 and multiplies to 75? 5 and 15.
x^2+5x+15x+75
x(x+5) 15(x+5)
(x+15) (x+5)
Zeroes are x= -5 and x= -15
Answer:q= (2C - fb)/f
Step-by-step explanation:
multiplying both sides by 2 we have,
2C = fb + fq,
subtract both sides by fb
fq = 2C - fb,
dividing both sides by f
q= (2C - fb)/f
Answer:
infinite
Step-by-step explanation:
Let the linear equation in two variables be ax+by+c=0
Put values


Hence for any values it has infinite number of solutions .
including x=1 and y=3
<h2>Steps:</h2>
So firstly, since we know that the coefficient of x² is 1, this means that this is our base equation:
y = x² + bx + c
Now, since we know that the roots are -7 and 1, set y = 0 and set x = -7 and 1 and simplify:

Now with this, we can set up a system of equations to solve for b and c. For this, I will be using the elimination method. For this, subtract the 2 equations:

Now that the c variable has been eliminated we can solve for b. For this, divide both sides by -8 and your first part of your answer is b = 6.
Now that we know the value of b, plug it into either equation to solve for c:

<h2>Answer:</h2>
<u>Putting it together, your final answer is x² + 6x - 7 = 0.</u>