Answer:
b)void aNonclassFunction (Banana co);
Explanation:
In the function definition you have to pass the tell the function which type of argument it is taking.In our case we are taking a variable co of Banana type passing it to the function named aNonclassFunction having no return type.
So the definition will be like this.
void aNonclassFunction (Banana co);
Answer:
Analog computers only work with continuous numerical data in analog quantities, digital computers can process both non-numerical and numerical data and a hybrid computer is a combination of both analog and digital. A hybrid computer has the accuracy of a digital computer paired with speed of an analog one.
Answer:
import java.util.Scanner;
public class ArraysKeyValue {
public static void main (String [] args) {
final int SIZE_LIST = 4;
int[] keysList = new int[SIZE_LIST];
int[] itemsList = new int[SIZE_LIST];
int i;
keysList[0] = 13;
keysList[1] = 47;
keysList[2] = 71;
keysList[3] = 59;
itemsList[0] = 12;
itemsList[1] = 36;
itemsList[2] = 72;
itemsList[3] = 54;
/* Your solution goes here */
for ( i = 0; i < SIZE_LIST; i++){
if (keysList[i]>50){
System.out.println(itemsList[i] + " "); } }
System.out.println("");
}
}
Explanation:
I will explain the whole program flow.
- There are two arrays here
- The first list (keysList) contains the following elements:
13 element at first position of the array (0th index)
47 element at second position of the array (1st index)
71 element at third position of the array (2nd index)
59 element at fourth position of the array (3rd index)
- The other list (itemsList) contains the following elements:
12 element at first position of the array (0th index)
36 element at second position of the array (1st index)
72 element at third position of the array (2nd index)
54 element at fourth position of the array (3rd index)
- The size of the array elements is fixed which is 4 and is stored in the variable SIZE_LIST.
- Then the loop starts. The loop contains a variable i which is initialized to 0. First it checks if the value of i is less than the size of the list. It is true as SIZE_LIST=4 and i=0.
- So the program control enters the body of the loop.
- In first iteration, IF condition checks if the i-th element of the keysList is greater than 50. As i=0 So the element at 0th index of the keysList is 13 which is not greater than 50 so the body of IF statement will not execute as the condition evaluates to false. The value of i increments by 1 so now i becomes 1.
- In next iteration loop again checks if the value of i is less than the size of the list which is true again so the body of the loop executes.
- IF condition checks if the i-th element of the keysList is greater than 50. As i=1 So the element at 1st index of the keysList is 47 which is not greater than 50 so the body of IF statement will not execute as the condition evaluates to false. The value of i is incremented by 1 so now i becomes 2.
- In next iteration loop again checks if the value of i is less than the size of the list which is true again as i= 2 which is less than SIZE_LIST so the body of the loop executes.
- IF condition checks if the i-th element of the keysList is greater than 50. As i=2 So the element at 2nd index of the keysList is 71 which is greater than 50 so the body of IF statement is executed as the condition evaluates to true. So in the body of the IF statement there is a print statement which prints the i-th element of the itemsList. As i = 2 so the value at the index 2 of the itemsList is displayed in the output which is 72. Next value of i is incremented by 1 so now i becomes 3.
- In next iteration loop again checks if the value of i is less than the size of the list which is true again as i= 3 which is less than SIZE_LIST so the body of the loop executes.
- IF condition checks if the i-th element of the keysList is greater than 50. As i=3 So the element at 3rd index of the keysList is 59 which is greater than 50 so the body of IF statement is executed as the condition evaluates to true. So in the body of the IF statement there is a print statement which prints the i-th element of the itemsList. As i = 3 so the value at the index 3 of the itemsList is displayed in the output which is 54. Next value of i is incremented by 1 so now i becomes 4.
- In next iteration loop again checks if the value of i is less than the size of the list which is now false as i=4 which is equal to the SIZE_LIST= 4. So the loop breaks.
- So the output of the above program is:
72
54
Answer:
cell address is the exact location of a particular cell of ms-excle
Explanation:
A1 refers to first row and first column.
A2 refers to second row first column.
i.e.
in 'A1' : 'A' indicate column { A= first column, B= second
column, C= third column. and soon.....}
'1' indicate row { 1 = first row, 2 = second row, 3= third row..... soon .......}
Answer:
twos complement value is (-2^15 -1) -32768 to 32767.
excess notation value is -32768 to 32767.
unsigned binary value is (2^16) 0 to 65535
Explanation:
Excess notation: used to represent signed integers. Always uses fixed number of bits with leftmost representing the sign.
Twos complement notation: As opposed to excess notation, a sign bit of 0 is used to represent the non-negative (+) sign and a 1 for the negative (-); again, zero is included in the non-negative set.
Unsigned Binary values: are binary values/bits that don't have signs
