Greater than (I'm like 80% sure of my answer)
Answer:
Distance from the airport = 894.43 km
Step-by-step explanation:
Displacement and Velocity
The velocity of an object assumed as constant in time can be computed as

Where
is the displacement. Both the velocity and displacement are vectors. The displacement can be computed from the above relation as

The plane goes at 400 Km/h on a course of 120° for 2 hours. We can compute the components of the velocity as


The displacement of the plane in 2 hours is


Now the plane keeps the same speed but now its course is 210° for 1 hour. The components of the velocity are


The displacement in 1 hour is


The total displacement is the vector sum of both



The distance from the airport is the module of the displacement:


Answer:
3° and 87°
Step-by-step explanation:
<em>here's</em><em> your</em><em> </em><em>solution</em>
<em> </em><em>=</em><em>></em><em> </em> we know that measure of complementary angle is 90°
=>. one angle is. = x
=> other angle is .= (19x + 30)
=> so, x + 19x + 30° = 90°
=> 20x + 30° = 90°
=> 20x = 60°
=> x = 60/20
=> x = 3°
hence one angle is 3° and other is 87°
hope it helps
Answer:
b < 50. The solution has infinite solutions because any number smaller than 50 would work, and their are infinite numbers smaller than 50.
Step-by-step explanation:
This is how I solved it.
2.5 multiplied by 3 is 7.5, which equals how many she takes a day.
Then I multiplied 7.5 by 10 = 75. I did that because the meds are taken for 10 days.
Also if you added 7.5 ten times is also 75.
So my final answer is that 75 tablets have been taken in total.