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2 years ago

Please help me with this math problem!! NO LINKS PLEASE!! DUE TONIGHT AT 11:59PM!! THANKS!! :)

Mathematics

1 answer:

siniylev [52]2 years ago

6 0

$\sin \gamma = \dfrac wk\\\\\\\tan \varphi = \dfrac mw\\\\\\\tan \gamma = \dfrac wm$

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X^2+7x-30 Factor the quadratic Show steps

DENIUS [597]

Answer:

(−3)(+10P)

Step-by-step explanation:

in pic

(Hope this helps can I pls have brainlist (crown) ☺️)

6 0

3 years ago

The interquartile range of a data set is 10 units. What does this represent?

Zepler [3.9K]

The interquartile range is from Q1 to Q3 and to get this you have to subtract Q2 by Q3. The 10 units represent that only 10 units are fit in the given range.

7 0

2 years ago

Read 2 more answers

Data collected over time on the utilization of a computer core (as a proportion of the total capacity) were found to possess a r

Marianna [84]

Answer:

The probability that the proportion of the core being used at any particular time will be less than 0.10 is 0.08146

Step-by-step explanation:

$\mu =\frac{\alpha }{\alpha +\beta } = \frac{1}{1 + \frac{\beta}{\alpha} }$ 1/3 0.33 = 33.33 %

The Probability of that the proportion of the core being used at any particular time will be less than 0.10 is given by

PDF = $\frac{x^{\alpha -1} (1-x)^{\beta -1} }{\int\limits^1_0 {u^{\alpha -1} (1-u)^{\beta -1}} \, du }$

where x = 0.1

α = 2 and β = 4

PDF = $\frac{0.0729 }{\int\limits^1_0 {u^{\alpha -1} (1-u)^{\beta -1}} \, du }$ = 1.458

CDF = $\frac{\int\limits^{0.1}_0 {t^{\alpha -1} (1-t)^{\beta -1}} \, du }{\int\limits^1_0 {u^{\alpha -1} (1-u)^{\beta -1}} \, du }$ = 0.08146

The probability that the proportion of the core being used at any particular time will be less than 0.10 = 0.08146.

3 0

3 years ago

Can someone please help me please

qwelly [4]

Answer:

$1) \dfrac{12+\sqrt{-16}}{4}=\dfrac{12+\sqrt{16i^{2}}}{4}\\\\\\=\dfrac{12+4i}{4}=\dfrac{12}{4}+\dfrac{4i}{4}\\\\\\= 3 + i$

Real part = 3 & imaginary part = 1

2) 4 + 7i - 8 = 4 -8 + 7i

= -4 + 7i

Real part = -4 & imaginary part = 7

$3)\dfrac{\sqrt{9}+\sqrt{-4}}{5}=\dfrac{3+\sqrt{4i^{2}}}{5}\\\\\\=\dfrac{3}{5}+\dfrac{2i}{5}\\\\\\Real \ part = \dfrac{3}{5} \ & \ imaginary \ part = \dfrac{2}{5}$

$4) -2-\sqrt{-25}=-2-\sqrt{25i^{2}}=-2-5i$

Real part = -2 & imaginary part = -5

$5)\dfrac{15-13i}{3}=\dfrac{15}{3}-\dfrac{13i}{3}\\\\\\Real \ part = \dfrac{15}{3} \ & \ imaginary \ part = \dfrac{-13}{3}$

b) 1) 6 + 4i

2) -12+ 5i

3) 5-14i

4 0

2 years ago

BD and AC are chords that intersect at point Y.

Sindrei [870]

Answer:

4 units

Step-by-step explanation:

The complete question is

BD and AC are chords that intersect at point Y. A circle is shown. Chords B D and A C intersect at point Y. The length of B Y is 3, the length of Y D is 8, the length of A Y is x, and the length of Y C is 6. What is the length of line segment AY?

The picture of the question in the attached figure

we know that

The Intersecting Chord Theorem states that: When two chords intersect each other inside a circle,the products of their segments are equal.

In this problem

$(BY)(YD)=(AY)(YC)$