No, because in the first one the 4 is negative, in the second it is positive
Answer:
(c) y-2 = -4(x-3)
Step-by-step explanation:
The point-slope equation of a line is ...
y -k = m(x -h) . . . . . . line through point (h, k) with slope m
For (h, k) = (3, 2), and m = -4, the equation of the line is ...
y -2 = -4(x -3)
we have
6x+3y=12 -----> line p
Find the slope
3y=-6x+12
y=-2x+4
m=-2
-4x=2y-2 -----> line Q
2y=-4x+2
y=-2x+1
m=-2
therefore
the lines are parallel because their slopes are equal
Assuming that the inequality you were going for was a ≤, set both polynomials less than or equal to 0.
x - 3 ≤ 0
x + 5 ≤ 0
For the first equation add 3 to both sides of the inequality. For the second, subtract 5 from both sides.
x ≤ 3
x ≤ - 5
These would be your solutions I guess, however, if you want to expand upon that, your actual answer is (- ∞, - 5] because if you were to plot these two inequalities on a number line, that is where the overlap would occur.
Answer:
first box is parallel
Second box perpendicular
Third box neither
Fourth box neither
Fifth box perpendicular
Sixth box is parallel
Why? Slopes of parallel lines are the same. Slopes of perpendicular lines are opposite reciprocals. (Example slope=1/2 a perpendicular line would be -2/1). Neither is just a when it’s not either parallel or perpendicular.
Hope this helps
