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MArishka [77]
3 years ago
6

In how many ways can a teacher arrange 5 students in the front row of a classroom with a total of 20 students?

Mathematics
1 answer:
makkiz [27]3 years ago
7 0
C, 60,480 i took thiis  before it easy as
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kkurt [141]

Answer:

D

Step-by-step explanation:

<em>for </em><em>you </em><em>to </em><em>find </em><em>x </em><em>you </em><em>first </em><em>have </em><em>to </em><em>find </em><em>the </em><em>adjacent</em><em> </em><em>of </em><em>the </em><em>4</em><em>5</em><em>°</em><em> </em><em>angle </em><em>you </em><em>can </em><em>do </em><em>that </em><em>by </em><em>using</em><em> </em><em>the </em><em>other </em><em>triangle.</em><em>u</em><em>s</em><em>i</em><em>n</em><em>g</em><em> </em><em>the </em><em>sin </em><em>ratio</em>

<em>sin60=</em><em>opposite</em><em>/</em><em>hypotenuse</em>

<em>sin60=</em><em>a/</em><em>7</em><em>√</em><em>3</em>

<em>a</em><em>=</em><em>1</em><em>0</em><em>.</em><em>5</em>

<em>then </em><em>after </em><em>you </em><em>have </em><em>found</em><em> </em><em>the </em><em>adjacent</em><em> </em><em>you </em><em>can </em><em>use </em><em>the </em><em>cos </em><em>ratio</em>

<em>cos45=</em><em>adjacent/</em><em>hypotenuse</em>

<em>cos45=</em><em>1</em><em>0</em><em>.</em><em>5</em><em>/</em><em>x</em>

<em>cos45x/</em><em>cos45=</em><em>1</em><em>0</em><em>.</em><em>5</em><em>/</em><em>cos45</em>

<em>x=</em><em>1</em><em>4</em><em>.</em><em>8</em><em>4</em><em>9</em>

<em>which </em><em>is </em><em>the </em><em>same </em><em>as </em><em>2</em><em>1</em><em>√</em><em>2</em><em> </em><em>over </em><em>2</em>

<em>I </em><em>hope</em><em> this</em><em> helps</em>

5 0
3 years ago
Read 2 more answers
Sadie computes the perimeter of a rectangle by adding the length, l , and width, w , and doubling this sum. Eric computes the pe
larisa [96]

a) P = 2(l+w)  Sadie

 P =2l+2w  Eric

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Eric: P = 2(30) +2(75) = 60+150 =210

4 0
3 years ago
Simplify using the laws of exponents (4^3)^-2 × (2^3)^4 ×(8/15)^-2​
katrin2010 [14]

Answer:

\dfrac{225}{64}

Step-by-step explanation:

(4^3)^{-2} \times (2^3)^4 \times (\dfrac{8}{15})^{-2} =

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= 2^{-12} \times 2^{12} \times \dfrac{225}{64}

= \dfrac{225}{64}

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Aleks04 [339]
There are 850 workers in the smallest building, 1350 workers in the second-largest building, and 1700 workers in the largest building.
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4 years ago
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90 ÷ 2 is the same as 1/2 of 90.

Either way you get 45.
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