Let's assume
boiling point is y
altitude is x
we are given
This relationship between altitude and boiling point is linear
At an altitude of 1000 feet, water boils at 210°F
so, first point is (1000,210)
so, x1=1000 , y1=210
At an altitude of 3000 feet, water boils at 206°F
so, second point is (3000,206)
so, x2=3000,y2=206
now, we can find slope
now, we can plug values
now, we can use point slope form of line
so, we can plug it
so, point slope form of line is
now, we can plug x=8000
and then we can solve for y
So,
the boiling point of water at an altitude of 8000 feet is 196°F..........Answer
Answer:
<h3>Move all the x terms to one side. Use inverse operations and add 1 5 x 15x 15x to both sides to keep the equation balanced. Solve by working backwards from the order of operations. This means we need to undo the −2 first by adding 2 to both sides of the equation to keep it balanced.</h3>
Answer:
QH = 227.8 km ≅ 228 km
Step-by-step explanation:
∵ The bearing from H to P is 084°
∵ The bearing from P to Q is 210°
∵ The distance from H to P = 340 km
∵ The distance from P to Q = 160 km
∴ The angle between 340 and 160 = 360 - 210 - (180 - 84) = 54°
( 180 - 84) ⇒ interior supplementary
By using cos Rule:
(QH)² = (PH)² + (PQ)² - 2(PH)(PQ)cos∠HPQ
(QH)² = 340² + 160² - 2(340)(160)cos(54) = 51904.965
∴ QH = 227.8 km ≅ 228 km
<span>14:42 = 14/42 = 1/3
</span>This ones right sorry answered wrong question lol
No the signs stay the same
