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Rom4ik [11]
3 years ago
13

The equation of the normal line

Advanced Placement (AP)
1 answer:
Sedaia [141]3 years ago
6 0

Answer:

D. y = 1/2x + 3/2

Explanation:

You probably already know the point slope equation:

y = m(x - x₀) + y₀

All you need is the slope and the (x₀, y₀).

The (x₀, y₀) could be solved by plugging in the given x=-1 value into the function.

m, the slope, is the same as a derivative; ie. a derivative is a slope.

So solve for the derivative and find the slope at x=-1.

Plug into point slope equation and simplify.

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What is the square root of 1.45?<br><br> Brainliest will be given for the correct answer.
charle [14.2K]

Answer:

√1.45 = 1.2041594578792

Explanation:

Step 1:

Divide the number (1.45) by 2 to get the first guess for the square root .

Step 2:

Divide 1.45 by the previous result. d = 1.45/0.725 = 2.

Average this value (d) with that of step 1: (2 + 0.725)/2 = 1.3625

previous value = 0.725 - 1.3625 = 0.6375.

0.6375 > 0.001

Now we repeat the step

Step 3:

Divide 1.45 by the previous result. d = 1.45/1.3625 = 1.0642201835.

Average this value (d) with that of step 2: (1.0642201835 + 1.3625)/2 = 1.2133600918

Error = new guess - previous value = 1.3625 - 1.2133600918 = 0.1491399082.

0.1491399082 > 0.001.

Step 4:

Divide 1.45 by the previous result. d = 1.45/1.2133600918 = 1.1950285903.

Average this value (d) with that of step 3: (1.1950285903 + 1.2133600918)/2 = 1.2041943411 (new guess).

Error = new guess - previous value = 1.2133600918 - 1.2041943411 = 0.0091657507.

0.0091657507 > 0.001.

Step 5:

Divide 1.45 by the previous result. d = 1.45/1.2041943411 = 1.2041245757.

Average this value (d) with that of step 4: (1.2041245757 + 1.2041943411)/2 = 1.2041594584

- previous value = 1.2041943411 - 1.2041594584 = 0.0000348827.

0.0000348827 <= 0.001. accuracy, we stop the iterations and use 1.2041594584 as the square root.

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A trapezoidal Riemann sum can be found by multiplying the width (the change in x) of each sub interval by the average of the y values of the two points at either end of the section and then adding up all of the sun intervals. Therefore, the trapezoidal approximation would equal 0.5(40) + 1.5(50) + 1(35) to get the answer of 130.
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