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3 years ago

Genes are sections of DNA that code for a particular trait. Genes are

2 answers:

7 0

The set of information that controls a trait; a segment DNA on a chromosome that codes for a specific trait. An abnormal condition that a person inherits through genes or chromosomes. Deoxyribonucleic acid; the genetic material that carries information about an organism and is passed on from parent to offspring.

Natasha2012 [34]3 years ago

4 0

The question is incomplete but by the understanding of gene it can be defined as:

Answer:

Genes can be defined as the segments of the DNA that contains the code for the specific type of protein.

It functions in one or more type of cells in the body. Different genes are functional in different cells of the body.

The genes that are functional in the heart are not functional in the liver and likewise different organs of the body has different functional genes.

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A deck of playing cards has 52 cards, of which 13 are diamonds. If you shuffle the deck well and turn over the top 4 cards, one

vampirchik [111]

Answer:

The correct solution is "0.002". A further solution is given below.

Explanation:

The given values are:

The total number of playing cards,

= 52 cards

Total number of diamonds,

= 13

Now,

The probability of top four cards will be:

= $P(First \ diamond)\times P(Second \ diamond)\times P(Third \ diamond)\times P(Fourth \ diamond)$ On putting the values, we get

= $\frac{13}{52}\times \frac{12}{51}\times \frac{11}{50}\times \frac{10}{49}$

= $0.25\times 0.23\times 0.22\times 0.20$

= $0.002$

3 0

3 years ago

Put these correlation coefficients in order from strongest first and the weakest last: +.22; +.77; -.66; -.79; -.33; +.89; -.94.

Vilka [71]

+.22; -.66;.77; 79; -.33; +.89; -.94.

4 0

3 years ago

Why is that surface area:Volume ratio so important? (About cells and microscopes)

OLga [1]

Answer:It affects the diffusion across a membrane

Explanation:

Since this is placed in the AP section, I assume it is AP Biology, which the syllabus puts emphasis on diffusion

The smaller the ratio is, the bigger the cell. SO, if the ratio is small enough, the molecule will not be able to diffuse through the membrane. Keep that in mind when you calculate different rations using the radius.

7 0

3 years ago

The length of a rectangle is 3 less than twice the width. If the area of the rectangle is 50 square inches, choose the equation

USPshnik [31]

Answer:

$w(2w-3)=50$

Explanation:

Let the length of the rectangle be $w$ units.

We were given that the length is 3 less than twice the width.

This implies that: $l=2w-3$

We have that the area of this rectangle is 50 square inches.

Recall that area of rectangle is given by:

$A=lw$

$\implies w(2w-3)=50$

Therefore the required equation is $w(2w-3)=50$

6 0

3 years ago

1. The rate at which people enter a movie theater on a given day is modeled by the function S defined by S(t) = 80 -12 cos 6 The

Arlecino [84]

Hi there!

To find the total amount of people that have ENTERED by t = 20, we must take the integral of the appropriate function.

$\text{Amount that entered} = \int\limits^{20}_{10} {S(t)} \, dt \\\\ = \int\limits^{20}_{10} {80 - 12cos(\frac{t}{5})} \, dt$

Evaluate using a calculator:

$= 899.97 \approx \boxed{900\text{ people}}$

To solve, we can find the total amount of people that have entered of the interval and subtract the total amount of people that have left from this value.

In other terms:
$\text{Amount of people} = \int\limits^{20}_{10} {S(t)} \, dt - \int\limits^{20}_{10} {R(t)} \, dt$

We can evaluate using a calculator (math-9 on T1-84):

$\text{\# of people} = \int\limits^{20}_{10} {80-12cos(\frac{t}{5})} \, dt - \int\limits^{20}_{10} {12e^{\frac{t}{10}}+20} \, dt$

$= 899.97 - 760.49 = 139.47 \approx \boxed{139 \text{ people}}$

If:
$P(t) = \int\limits^t_{10} {S(t) - R(t)} \, dt$

Then:

$\frac{dP}{dt} = P'(t)= \frac{d}{dt}\int\limits^t_{10} {S(t) - R(t)} \, dt = S(t) - R(t)$

Evaluate at t = 20:

$S(20) = 80 - 12cos(\frac{20}{5}) = 87.844\\\\R(20) = 12e^{\frac{20}{10}} + 20 = 108.669$

$S(20) - R(20) = 87.844 - 108.669 = -20.823$

This means that at t = 20, there is a NET DECREASE of people at the movie theater of around 20.823 (21) people per hour.

To find the maximum, we must use the first-derivative test.

Set S(t) - R(t) equal to 0:

$80 - 12cos(\frac{t}{5}) - 12e^{\frac{t}{10}} - 20 = 0\\\\60 - 12(cos(\frac{t}{5}) + e^{\frac{t}{10}})= 0$

Graph the function with a graphing calculator and set the function equal to y = 0:

According to the graph, the graph of the first derivative changes from POSITIVE to NEGATIVE at t ≈ 17.78 hours, so there is a MAXIMUM at this value.

Thus, at t = 17.78 hours, the amount of people at the movie theater is a MAXIMUM.

8 0

2 years ago