We know that
The inscribed angle Theorem states that t<span>he inscribed angle measures half of the arc it comprises.
</span>so
m∠D=(1/2)*[arc EFG]
and
m∠F=(1/2)*[arc GDE]
arc EFG+arc GDE=360°-------> full circle
applying multiplication property of equality
(1/2)*arc EFG+(1/2)*arc GDE=180°
applying substitution property of equality
m∠D=(1/2)*[arc EFG]
m∠F=(1/2)*[arc GDE]
(1/2)*arc EFG+(1/2)*arc GDE=180°----> m∠D+m∠F=180°
the answer in the attached figure
The solution is (-2,4) she right both have the same solution because if you solve both of them you will get (-2,4)
What needs to be done first is to add up females and males that have passed.
42 + 14 = 56
so out of 56 students who passed 42 females passed 42/56 = 3/4 = 0.75
out of 56 students who passed, 14 males passed which turns into 14/56 = 1/4 = 0.25
check work; 0.75 + 0.25 = 1.00
NOW WE ARE DOING FAILS.
15 + 5 = 20
so out of 20 students who failed, 15 females failed so it turns into 15/20 = 3/4 = 0.75
out of 20 students who failed, 5 males failed. 5/20 = 1/4 = 0.25
check work; 0.75 + 0.25 = 1.00
i hope this helped! :)
The answers are E.) y-int is (0,4), F.) domain of F(x) is all rel numbers , and C.) it is increasing