Find the length of the segment with endpoints of (3,2) and (-3,-6).

1 answer:

5 0

The formula of the length of the segment AB:
$A(x_A;\ y_A);\ B(x_B;\ y_B)\\\\|AB|=\sqrt{(x_B-x_A)^2+(y_B-y_A)^2}$
We have:
$A(3;\ 2)\to x_A=3;\ y_A=2\\\\B(-3;\ -6)\to x_B=-3;\ y_B=-6$
Substitute:
$|AB|=\sqrt{(-3-3)^2+(-6-2)^2}=\sqrt{(-6)^2+(-8)^2}\\\\=\sqrt{36+64}=\sqrt{100}=10$
Answer: B) 10.

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