The more appropriate measures of center and spread are:
- A. Better measure of spread: the interquartile range (IQR)
- B. Better measure of center: the median
<h3>Which measures are best for the given data?</h3>
The better measure of the middle would be the median because mean is affected by low and high values which are present in the given data set.
As mean is not being used, standard deviation should not be used for the same reason. This leaves us with the interquartile range which is best because it does not take outliers into account.
Find out more on the Interquartile Range at brainly.com/question/12568713.
#SPJ1
Remember
(ab)(cd)=(a)(b)(c)(d)=(ac)(bd),
and
(x^m)(x^n)=x^(m+n)
(9x^2y^3)(7xy^2)=
(9)(x^2)(y^3)(7)(x)(y^2)=
(9)(7)(x^2)(x)(y^3)(y^2)=
(63)(x^3)(y^5)=
63x^3y^5
If Reginald answered 78% correctly out of a total 100%, we can subtract 78 from 100:
100 - 78 = 22
He answered 22% of the question incorrectly. But how do we find the bottom number? Remember what we said earlier. The <u>total</u> is 100%. He got 22% out of 100% wrong. Wouldn't that be 
?
Now that we know our fraction, we can reduce it. Let's start by dividing our fraction in half:
= 
Can we reduce that any more? No, because 11 can not be divided by anything else.
If you want the first fraction, go with , but if they want a reduced fraction, then would be best.
