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olga2289 [7]
3 years ago
7

Explain how you used the bar model in 14-7=7

Mathematics
1 answer:
mezya [45]3 years ago
3 0
Just say I have 14 donuts total and I ate seven in one week that is 1 per day so u would 14 and then leave out 7 of that 14 make sense?
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From a standard deck of cards, a 5-card hand is dealt. Calculate the number of hands that contain 4 diamonds and 1 black king
rjkz [21]

Answer:

1430

Step-by-step explanation:

Given that a standard deck of cards is 52 cards, we have 13 Diamonds and we need 4 diamonds.

Hence, we have 13C4.

Also, we have 4 kings in a standard deck of cards, and in which we have 2 black kings but we need 1 king.

Hence we have a 2C1

Therefore:

13C4 * 2C1

=> 13! ÷ [4! (13 - 4)!] * 2! ÷ [1! (2-1)!]

=> 13! ÷ [4! (9)!]

=> (1 x 2 x 3 x 4 x 5 x 6 x 7 x 8 x 9 x 10 x 11 x 12 x 13) ÷ [(1 x 2 x 3 x 4) (1 x 2 x 3 x 4 x 5 x 6 x 7 x 8 x 9)]

=> (10 x 11 x 12 x 13) ÷ 24

=> (17160 ÷ 24) * (24 ÷ 6)

=> 715

2! ÷ [1! (2-1)!]

=> 2

Hence, we have 715 * 2

=> 1430

Hence, in this case, the correct answer to the question is 1430

7 0
3 years ago
Older Orchards need more hives per acre Caleb has decided to place 6 hives for every 2 acres on an older peach orchard Zeke one
Serhud [2]

Answer:

Zeneca did not follow the directions. In order to follow Caleb's directions, Zelda would need to bring in 6 hives for every 2 acres of peaches.

If there are 30 acres, this means he would 15 groups of 6 hives (90 hives). He only brought 10.

Step-by-step explanation:

7 0
3 years ago
Actor the expression 16x+8x+1 16x 28x +11-​
Gwar [14]
<h3>Explanation:</h3>

\large \purple {\sf { {16x}^{2}  + 8x + 1}}

\large \pink {\sf { =  {(4x)}^{2}  + 2(4x)(1) +  {(1)}^{2}}}

\large \orange {\sf { = {(4x + 1)}^{2} }}

<h2>Answer:</h2>

\large \green {\sf {{16x}^{2}  + 8x + 1 =  {(4x + 1)}^{2}}}

6 0
3 years ago
100 POINTS PLEASE ANSWER FULLY!!
Kruka [31]

Answer:

15

Step-by-step explanation:

6 0
3 years ago
Read 2 more answers
Which system of equations does not have a real solution?
dolphi86 [110]

Answer:

It's A.

Step-by-step explanation:

Let's look at option A:

From the second equation y =  -10 - x. Substituting in the first equation:

-10 - x = x^2 + 3x - 5

x^2 + 4x + 5 = 0

Checking the discriminant b^2 - 4ac we get 16 - 4*1*5 = -4 so there are no real roots. (A negative discriminant means no real roots).

So A has no real solution.

B.

x^2 + 3x - 5 =  (20 - 4x)/5 = 4 - 0.8x

x^2 +3.8x - 9 = 0

b^2 - 4ac = (3.8)^2 - 4*1*-9 = 50.44 (positive) so there are real roots.

C.

x^2 + 3x - 5 =  -9 - x

x^2 + 4x + 4 = 0

b^2 - 4ac =  4^2 - 4*1*4 = 0  so there are real roots.

7 0
3 years ago
Read 2 more answers
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