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natali 33 [55]
3 years ago
12

Please help me with this question, image attached.

Mathematics
1 answer:
goldfiish [28.3K]3 years ago
8 0
You need to 8 + 4 = 12 and take the half of 12 and start at -4 and count up 6
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3. If you were to graph the equation y = -x + 1 and graph the equation y
Nat2105 [25]

Answer: (3, -2)

Step-by-step explanation: graphed both of em on desmos and thats the intersection.

5 0
3 years ago
2/x + 3/y = 13 ; 5/x - 4/y = -2​
Tomtit [17]

Given that

(2/x)+(3/y) = 13--------(1)

(5/x)-(4/y) = -2 -------(2)

Put 1/x = a and 1/y = b then

2a + 3b = 13 ----------(3)

On multiplying with 5 then

10a +15 b = 65 -------(4)

and

5a -4b= -2 ----------(5)

On multiplying with 2 then

10 a - 8b = -4 -------(6)

On Subtracting (6) from (4) then

10a + 15b = 65

10a - 8b = -4

(-)

_____________

0 + 23 b = 69

______________

⇛ 23b = 69

⇛ b = 69/23

⇛ b =3

On Substituting the value of b in (5)

5a -4b= -2

⇛ 5a -4(3) = -2

⇛ 5a -12 = -2

⇛ 5a = -2+12

⇛ 5a = 10

⇛ a = 10/5

⇛ a = 2

Now we have

a = 2

⇛1/x = 2

⇛ x = 1/2

and

b = 3

⇛1/y = 3

⇛ y = 1/3

<u>Answer :-</u>The solution for the given problem is (1/2,1/3)

<u>Check</u>: If x = 1/2 and y = 1/3 then

LHS = (2/x)+(3/y)

= 2/(1/2)+3/(1/3)

= (2×2)+(3×3)

= 4+9

= 13

= RHS

LHS=RHS is true

and

LHS=(5/x)-(4/y)

⇛ 5/(1/2)- 4/(1/3)

⇛(5×2)-(4×3)

⇛ 10-12

⇛ -2

⇛RHS

LHS = RHS is true

5 0
3 years ago
The number of girls at middle school cyber summer camp was six more than twice the number of boys. There were a total of 156 mid
nordsb [41]
Ok so if you did 156-6 (considering it was 6 more you want to subtract it) and then because the girls was doubled the boys (you are now at 150) you must divide that by 3 which will give you 50. But you need to double it (for girls) which is 100 and then you have 50 left over which is for the boys. Boys=50 girls=106
8 0
3 years ago
A regular six-sided die is rolled 1000 times. Use the binomial distribution to determine the standard deviation for the number o
ANTONII [103]

The standard deviation for the number of times an odd number is rolled is 15.8

<h3>How to determine the standard deviation?</h3>

The given parameters are:

Die = regular six-sided die

n = 1000

The probability of rolling an odd number is:

p = 1/2 = 0.5

The standard deviation is then calculated as;

\sigma = \sqrt{np(1 - p)

This gives

\sigma = \sqrt{1000 * 0.5 * (1 - 0.5)

Evaluate the products

\sigma = \sqrt{250

Evaluate the root

\sigma = 15.8

Hence, the standard deviation is 15.8

Read more about standard deviation at:

brainly.com/question/16555520

#SPJ1

8 0
2 years ago
Help me out! I always mark brainliest. Unless of course, it is incorrect or inadequate. Please include how you did the problem.
Charra [1.4K]
If 2 + 5i is a zero, then by the complex conjugate root theorem, we must have its conjugate as a zero to have a polynomial containing real coefficients. Therefore, the zeros are -3, 2 + 5i, and 2 - 5i. We have three zeros so this is a degree 3 polynomial (n = 3).
f(x) has the equation
                        f(x) = (x+3)(x - (2 + 5i))(x - (2 - 5i))
If we expand this polynomial out, we get the simplest standard form
                        f(x) = x^3-x^2+17x+87
Therefore the answer to this question is f(x) = x^3-x^2+17x+87
5 0
3 years ago
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