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Brrunno [24]
3 years ago
7

Questions 1 . 2 . 3 . 4

Mathematics
1 answer:
jolli1 [7]3 years ago
6 0
1.
A.add=12
B. subtract=7
C. subtract= -4
D .add=9
E. subtract=2
F. subtract= -2
G. add= -14
H. subtract= -1

2.
A.1
B.13
C.5
D.-1
E.54
F.40
G.40
H.-3

3.
A.-24
B. 24
C. -32
D. 30
E. -60
F. -40
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Answer:

The answer is option 2.

Step-by-step explanation:

Firstly, you must factorize the possible expressions :

\frac{ {x}^{2} - 2x - 15 }{x - 3}  \div  \frac{x - 5}{ {x}^{2} - 9 }

=  \frac{(x - 5)(x + 3)}{x - 3}  \div  \frac{x - 5}{(x - 3)(x  + 3)}

Next you have to divide by converting to multiplication :

= \frac{(x - 5)(x + 3)}{x - 3}  \times  \frac{(x - 3)(x + 3)}{x - 5}

Lastly, you can cut out the similar expressions :

=  \frac{(x - 5)(x + 3)(x - 3)(x + 3)}{(x - 3)(x  -  5)}

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Answer:

(2,4)

Step-by-step explanation:

When graphed the lines intersect at point (2,4) which is the solution.

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Answer:

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Step-by-step explanation:

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With some simple rearrangement, we can rewrite the numerator as

2x^3 - 3x^2 - x + 4 = 2(x^3 - x) - 3x^2 + x + 4 \\\\ ~~~~~~~~ = 2x(x^2-1) - 3(x^2 - 1) + x + 1 \\\\ ~~~~~~~~ = (2x-3)(x^2-1) + x+1

Then factorizing the difference of squares, x^2-1=(x-1)(x+1), we end up with

\dfrac{2x^3 - 3x^2 - x + 4}{x^2 - 1} = \dfrac{(2x-3)(x-1)(x+1) + x+1}{(x-1)(x+1)} \\\\ ~~~~~~~~ = \boxed{2x-3 + \dfrac1{x-1}}

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What are the characteristics of the graph of the inequality x ≥ -2? The ray will move to the left. The ray will move to the righ
Alenkasestr [34]

Answer:

Step-by-step explanation:

The inequality x ≥ -2 is graphed on a number line.  -2 is the smallest possible value.  All subsequent values are larger and therefore lie to the right of -2.

Thus, the following are true:

1.  The ray will move to the right (because x begins at -2 and increases, which means moving to the right on the number line).

2.  It will use a closed circle (because x = -2 is part of the solution set).

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