Q1
I like to use the standard form to write the equation of a perpendicular line, especially when the original equation is in that form. The perpendicular line will have the x- and y-coefficients swapped and one negated (remember this for Question 3). Thus, it will be
... 5x - 2y = 5(6) - 2(16) = -2
Solving for y (to get slope-intercept form), we find
... y = (5/2)x + 1 . . . . . matches selection C
Q2
The given equation has slope -3/6 = -1/2, so that will be the slope of the parallel line. (matches selection A)
Q3
See Q1 for an explanation. The appropriate choice is ...
... B. 4x - 3y = 5
Q4
The given line has slope -2, so you can eliminate all choices except ...
... D. -2x
Q5
The two lines have the same slope (3), but different intercepts, so they are ...
... A. parallel
Answer:
Your answer is correct... it's no.3 ... but if you multiply a inequality by a negative value the inequality sign changes.. like if you habe greater than it'll be less than... Keep that in mind too
The correct answer is the last one listed: the statement not supported by the graph is that a stock purchased in 2006 has not yet recovered the losses from 2008. That is not true.
Answer:
y= 6/5x + 2
If you substitute the points (5,8) you get:
8 = 6/5 × 5 + 2
8 = 6 + 2
Step-by-step explanation:
