Answer:
A=24, B=40, P=60
Step-by-step explanation:
<em>given: </em>
<em>P+A+B=124</em>
<em>2P+B=160</em>
<em>P+2A+2B=188</em>
___________
P=188-2A-2B
P=124-A-B
188-2A-2B=124-A-B
188-A-B=124
188=124+A+B
A+B=64
___
P+A+B=124
P=60
___
2P+B=160
120+B=160
B=40
___
A+B=64
A=24
___
If we substitute each variable in the three given equations for these values, the equations hold true. Therefore, these are the correct values.
Let the number of red, black, green and blue balls be R, B, G, U respectively.
B=R (There are as many black balls as red balls)
G+R=10 so G=10-R (Green balls and red balls should add up to 10)
R+10=U (There should be 10 more blue balls than red balls)
The minimal number of balls is 2, 304 so we have the following inequality:
R+B+G+U≥ 2,304
R+(R)+(10-R)+ (R+10)≥2,304
4R≥2,304
R≥2,304/4=576 so R=576
Answer: 576
Answer:
Final answer is 
.
Step-by-step explanation:
Given that P(A)= .50, P(B)=.80 , and P(A and B)=.20.
Now we need to find about what is the value of P(B/A).
So apply the formula of compound probability :
P(A and B) = P(A)*P(B/A)
Plug the given values into above formula
0.20 = 0.50*P(B/A)
0.50*P(B/A) = 0.20
Hence final answer is .
94.5
Let me know if I’m right
It is unlikely is the expected answer. (<em>c</em><em>o</em><em>r</em><em>r</em><em>e</em><em>c</em><em>t</em><em> </em><em>o</em><em>n</em><em>e</em><em>)</em>
Hope this helps.
