For
y = (x^2 -4)/((x +2)(x^2 -49))
the numerator factors to (x -2)(x +2), so the factor of (x +2) will cancel with that in the denominator, leaving
y = (x -2)/(x^2 -49)
There are points of discontinuity at the hole, x=-2, and at each of the vertical asymptotes, at x=-7, +7.
The horizontal asymptote is y=0.
Answer:
Solution: (-1, -1)
Step-by-step explanation:
y=4x+2
y=-4/3x-2
Solve by graphing.
First, you need to plot the y-intercept.
y=4x+<u>2</u>
2 will be your y-intercept.
Next, you plot your slope.
y=<u>4x</u>+2
From your y-intercept, you will go up 4 and right one space, if you run out of space go down 4 and left 1.
Now repeat the same steps for the next one.
y=-4/3x<u>-2</u>
Plot your y-intercept.
y=<u>-4/3x</u>-2
because your slope is negative you will go down 4 and right 3, if you run out of room go up 4 and left 3.
Then draw connecting lines and wherever the lines intersect, that's going to be your solution. In this case, the solution is (-1, -1).
Hope this helps :)
We have that
y< 6x-3
using a graph tool
see the attached figure
the answer in the attached figure
since the equation is c=9.5t, Sanjay paid c=9.5 x 14 shirts he bought. which =$133
for 1st
use the formula of inlargement
A(x,y)when enlarging by scale factor k gives A'(kx,ky)
for 2nd
a=
(2a+3)-(a-5)(2a+2)+a^2
b=
3y(7y-8)
