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Sunny_sXe [5.5K]
3 years ago
12

Which equation has the soluion x=4

Mathematics
1 answer:
AfilCa [17]3 years ago
4 0

Answer:

3x=12

Step-by-step explanation:

3 times X with x being 4 making it 12 so X=4 and 3x=12

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Marshall and Graham both lift a 50 lb. weight. Graham lifts his weight in 5 seconds. Marshall takes 7 seconds. Which of the foll
Alla [95]

Answer:

B. Graham had more power than Marshall

Explanation:

Graham put more power into lifting his weight and therefore he lifted it 2 seconds faster than Marshall.

3 0
3 years ago
What is 2 3/7 divided 5 1/5
DaniilM [7]

In order to find the answer to this question you must change the mixed number into improper fractions (you do that by multiplying the denominator to the whole number then add the numerator and keep the denominator the same) then repeat the same rules you would do when dividing normal fractions. (use KCF) Then you solve.

2\frac{3}{7} \div 5\frac{1}{5}

2\frac{3}{7} = \frac{17}{7}

5\frac{1}{5} = \frac{26}{5}

\frac{17}{7} \div\frac{26}{5} =

\frac{17}{7} \times\frac{5}{26}

17 \times 5 =85

7 \times 26 = 182

= \frac{85}{182}

Therefore your answer is "85/182."

Hope this helps.

3 0
3 years ago
In front of a store, there is a row of parking spaces. Cars park parallel to one another, with the front of each car facing the
Gelneren [198K]

The width used for the car spaces are taken as a multiples of the width of

the compact car spaces.

Correct response:

  • The store owners are incorrect
<h3 /><h3>Methods used to obtain the above response</h3>

Let <em>x</em><em> </em>represent the width of the cars parked compact, and let a·x represent the width of cars parked in full size spaces.

We have;

Initial space occupied = 10·x + 12·(a·x) = x·(10 + 12·a)

New space design = 16·x + 9×(a·x) = x·(16 + 9·a)

When the dimensions of the initial and new arrangement are equal, we have;

10 + 12·a = 16 + 9·a

12·a - 9·a = 16 - 10 = 6

3·a = 6

a = 6 ÷ 3 = 2

a = 2

Whereby the factor <em>a</em> < 2, such that the width of the full size space is less than twice the width of the compact spaces, by testing, we have;

10 + 12·a < 16 + 9·a

Which gives;

x·(10 + 12·a) < x·(16 + 9·a)

Therefore;

The initial total car park space is less than the space required for 16

compact spaces and 9 full size spaces, therefore; the store owners are

incorrect.

Learn more about writing expressions here:

brainly.com/question/551090

5 0
2 years ago
Please help I Think I'm wrong!!!!
Allisa [31]
2n+2(n-4)=56
2n+2n-8=56
4n-8=56
4n=64
n=16

1st side is 16
2nd side is 12
8 0
3 years ago
What is 9 to the 3 halfs power
timurjin [86]
9 to the 3 half power is 27. Hope that's what your wanting to know.
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3 0
3 years ago
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