The molar mass of the compound:
If the solution has an osmotic pressure of 8.44 torr, then the molar mass of the unknown non-electrolyte is 223.14 g.
What is osmosis?
- Osmosis is defined as the flow of solvent molecules through semi-permeable membrane.
- Osmotic pressure is the pressure applied to stop the flow of solvent molecules.
- It is a colligative property that means osmotic pressure depends on the number of solute particles .
Therefore,
π
( for electrolytes)
Where, π= Osmotic pressure
i = Van 't Hoff factor
n= moles
R= Gaseous constant = 62.363577 L torr 
T= Temperature
V= Volume of solution
Given:
T= 298K
V= 150 mL= 0.150 L
Given mass of unknown electrolyte= 15.2 mg = 15.2 x 
g
Osmotic pressure= 8.44 torr
Molar mass= ?
For non-electrolytes:
πV = n RT
πV=
RT
Calculations:
Putting the given values in the formula:
8.44 x 0.150 =15.2 x / M x 62.36 x 298
1.266 = 282.5/M
M = 282.5/1.266
M = 223.14 g
Therefore,
The molar mass of the unknown non-electrolyte is 223.14g.
Learn more about Osmotic pressure here,
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Answer:
It is True.
Explanation:
Investigators use this tactic to see if the suspect is recalling by memory and if they will change their story after being asked to recall backwards.
Answer:
Diamond
Explanation:
As light moves from a less dense medium to a denser medium it slows down.
This is because the wave length of the light reduces. The denser the medium the less the wavelength. Diamond is the most dense solid among the provided choices thus light travelling through it has the least wavelength.
Answer:
Molarity of Na₂CO₃ = 0.25M
% mass = 2.69
Explanation:
Molarity means mole of solute in 1L of solution
Molar mass of solute (Na₂CO₃) = 105,98 g/m
Moles = mass / molar mass → 6.73 g / 105.98 g/m = 0.0635 m
Mol/L = [M]
0.0635 mol/0.250L = 0.25M
Density of solution = Solution mass / Solution volume
1 g/ml = Solution mass / 250 mL → Solution mass is 250g
% mass will be:
In 250 g of solution we have 6.73 g of solute
in 100 g of solution we have (100 . 6.73)/250 = 2.69
Make an observation.
Ask a question.
Form a hypothesis, or testable explanation.
Make a prediction based on the hypothesis.
Test the prediction.
Iterate: use the results to make new hypotheses or predictions. Hope this helps
