A non-coding region of a gene and introns encoding region of a gene are the substitution mutation in eukaryotis gene which are likely to be silent.
E option is the correct.
Explanation:
Silent mutation is a change in a nucleotide sequence in a gene which encodes a protein. Silent mutation do not cause any change in the amino acid sequence of the protein formed by the mutated gene.
They have been labelled as evolutionarily neutral.
The amino acid which even if gets replaced has same properties as the one which would have been encoded by the original triplet.
The substitution mutation is a change in nucleotide by getting their functional groups change as Adenine to Guanine.
The non-coding regions as intron if have substitution mutation it would be a silent mutation. Any single nucleotide mutation which disrupts slicing signal causes no protein formation.
Perhaps the answer is "physical characteristics". I am simply making an educated guess, however I do know early philosophers classified organisms into two groups, Plants and Animals, and identified them based on physical characteristics.
Answer:
i think its c, but could you tell me if its right or not?
rate 1 if its not right
Explanation:
Answer:
405
Explanation:
Gregor Mendel worked with pea plant and observed the inheritance of seed colour and shape in the plant. This is a dihybrid cross involving two genes; one coding for seed colour and the other for seed shape. The allele for yellow seed (Y) is dominant over green (y) in the first gene, while the allele for round seed (R) is dominant over wrinkled seed (r) in the second gene.
When Mendel crossed truebreeds i.e. homozygous parents, he got a F1 generation which is heterozygous for both traits (YyRr). He crossed two heterozygous plants, and according to the law of independent assortment, four possible chromosome combinations of gametes were produced viz: YR, Yr, yR, yr.
Mendel discovered that from a cross involving two hybrid genes, 16 variations were possible. In the genetic make-up, the kinds of F2 offsprings possible from this dihybrid cross are; Yellow round, Yellow wrinkled, Green round and Green wrinkled in a theoretical ratio 9:3:3:1 respectively.
According to the question, 720 offsprings were produced. Therefore, to get the number of progeny with yellow round seeds, the ratio will be used.
The ratio of yellow round seeds in Mendel's dihybrid cross is 9/16, hence, among 720 offsprings, we will have about- 9/16 × 720 = 405 pea plants with yellow and round seeds.