Answer:
Explanation:
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Answer:
a) the average CPI for machine M1 = 1.6
the average CPI for machine M2 = 2.5
b) M1 implementation is faster.
c) the clock cycles required for both processors.52.6*10^6.
Explanation:
(a)
The average CPI for M1 = 0.6 x 1 + 0.3 x 2 + 0.1 x 4
= 1.6
The average CPI for M2 = 0.6 x 2 + 0.3 x 3 + 0.1 x 4
= 2.5
(b)
The average MIPS rate is calculated as: Clock Rate/ averageCPI x 10^6
Given 80MHz = 80 * 10^6
The average MIPS ratings for M1 = 80 x 10^6 / 1.6 x 10^6
= 50
Given 100MHz = 100 * 10^6
The average MIPS ratings for M2 = 100 x 10^6 / 2.5 x 10^6
= 40
c)
Machine M2 has a smaller MIPS rating
Changing instruction set A from 2 to 1
The CPI will be increased to 1.9 (1*.6+3*.3+4*.1)
and hence MIPS Rating will now be (100/1.9)*10^6 = 52.6*10^6.
<span>B. Efficiency
(</span><span>effective training </span><span>techniques)</span>
Look this up on Quizlet. Besure to check the question and the answers carefully by using "define + the vocabulary word" you think answers the question.
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<span>AP Comp Sci Chapter 5</span>
Answer:
Explanation:
Given
Power at point A = 100W
Power at point B = 90W
Required
Determine the attenuation in decibels
Attenuation is calculated using the following formula
Where 
t and 
t
Substitute these values in the given formula
<em>(Approximated)</em>
