If you mean what goes in the blanks, it is 5 for the first empty box and 10 for the second empty box.
Answer:79 , 80 , 81
Step-by-step explanation:What three consecutive integers have a sum of 240? What three consecutive integers have a sum of 240? Which means that the first number is 79, the second number is 79 + 1 and the third number is 79 + 2. Therefore, three consecutive integers that add up to 240 are 79, 80, and 81.
Answer:
5/4k^2
Step-by-step explanation:
P=5\dfrac{k}{6}\times \dfrac{3}{2k^3}.
We will be using the following property of exponents:
\dfrac{a^x}{a^y}=a^{x-y}.
We have
P\\\\\\=5\dfrac{k}{6}\times\dfrac{3}{2k^3}\\\\\\=\dfrac{5}{6}\times\dfrac{3}{2}k^{1-3}\\\\\\=\dfrac{5}{4}k^{-2}=\dfrac{5}{4k^2}.
Thus, the required product is \dfrac{5}{4k^2}.
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