Answer:
Resistance, 
Explanation:
Given that,
Voltage of the battery, V = 9 volts
Current produced in the circuit, I = 17 A
We need to find the resistance when shorted by a wire of negligible resistance. It is a case of Ohm's law. The voltage is given by :
So, the resistance in the circuit is 0.529 ohms. Hence, this is the required solution.
Answer:
Explanation:
Total resistance of 2 bulb in series
= 100 +100 = 200 ohm
current in each bulb
= 9/200 = .045 A
In case of parallel combination of bulb
total resistance
= 100 x 100 / (100+100)
50 ohm
current in the main circuit
= 9 / 50 A
current in each bulb
= 9 / (2 x 50)
.09
So in the second case current is more , hence heat generated too will be more . So brightness too will be more.
First set ( in series ) will be dimmer.
Answer:
25m/s
Explanation:
p=mv
75 = 3v
v = 75/3
v = 25 m/s
If you want to verify your answer, just insert the value of v to the equation.
