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3 years ago

Help plz Which statement is true about transmission and absorption?

Physics

1 answer:

LiRa [457]3 years ago

7 0

The answer is A.

I just took the test.

I hope this helps. :)

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What discovery led J.J. Thomson to decide that atoms were not indivisible, but are actually composed of smaller parts? Thomson u

Arada [10]

Answer:

Thomson used a beam of negatively charged particles. Explanation: It was on a test i got it right.

8 0

3 years ago

Read 2 more answers

A force in the negative x-direction is applied for 27 ms to a 0.4 kg mass initially moving at 14 m/s in the x-direction. The for

noname [10]

Answer:

-67 m/s

Explanation:

We are given that

Mass of ball,m=0.4 kg

Initial speed,u=14 m/s

Impulse,I=-32.4 N-s

Time,t=27 ms= $27\times 10^{-3} s$

We have to find the mass's velocity in the x- direction.

We know that

$Impulse=mv-mu$

Substitute the values

$-32.4=0.4v-0.4(14)$

$-32.4+0.4(14)=0.4 v$

$-26.8=0.4v$

$v=\frac{-26.8}{0.4}=-67m/s$

6 0

4 years ago

What does the term "heat capacity" refer to?

kenny6666 [7]

Answer:

option C is correct

.............,

4 0

3 years ago

Read 2 more answers

A blue supergiant star has surface temperature 27 kK and has total power output 100000 times that of the Sun.

Free_Kalibri [48]

Answer:

Wien peak ( λmax ) is 107.40 nm

radius of super giant is 1.086 × $10^{10}$ m

Explanation:

given data

temperature 27 kK

power = 100000 times of Sun

Sun radius = 6.96 × 10^8 m

to find out

Wien peak ( λmax ) and radius of supergiant (r)

solution

we will apply here first wien law to find Wien peak that is

λmax = b / t

λmax = 2.9 × $10^{-3}$ / 27000 = 1.0740 × $10^{-7}$

so Wien peak ( λmax ) is 107.40 nm

and

now we apply steafay law that is

P = σ × A × $T^{4}$ .........................1

and we know total power output 100000 time of Sun

so we say

4πr²s $T^{4}$ = 100000 × 4πR²s $Ts^{4}$

r² = 100000 × R² $Ts^{4}$ / $T^{4}$

put here value

r² = 100000 × (6.96× $6000^{8}$ )² × $6000^{4}$ / $27000^{4}$

r² = 1.18132 × $10^{20}$

r = 1.086 × $10^{10}$ m

so radius of super giant is 1.086 × $10^{10}$ m

3 0

4 years ago

Help me and I'll make u Brainliest and follow u

frosja888 [35]

26. D. crushing the sugar cube and dissolving it in water.

27. A. atom

28. B. molecule

29. B. plum pudding model of Joseph John Thomson

30. B. He used cathode ray tubes which showed that all atoms contain tiny negatively charged subatomic particles or electrons

31. D. protons and neutrons are relatively heavier than electrons.

6 0

3 years ago