Answer:
75 m/s
Explanation:
We can apply motion equations here
V = U + a * t
V = velocity @ t time
U = initial velocity
a = acceleration
t = time taken
V = U + a * t
V = 0+ 3 * 25
V = 75 m/s
After 25 seconds , subjected to the given acceleration velocity is increased from 0 to 75 m/s
Answer:
E. greater than the angle of incidence.
Explanation:
Snell's law states that:
(1)
where
are the refractive index of the first and second medium
are the angle of incidence and refraction, respectively
For light moving from water to air, we have:
(index of refraction of water)
(index of refraction of air)
Substituting into (1) and re-arranging the equation, we get
which means that
so, the correct answer is
E. greater than the angle of incidence.
Answer:
a. same
b. less
c. same
d. same?
Explanation:
the mass will always be the same no matter where it is. the weight however depends on the gravity.
Answer:
The work done on the hose by the time the hose reaches its relaxed length is 776.16 Joules
Explanation:
The given spring constant of the of the spring, k = 88.0 N/m
The length by which the hose is stretched, x = 4.20 m
For the hose that obeys Hooke's law, and the principle of conservation of energy, the work done by the force from the hose is equal to the potential energy given to the hose
The elastic potential energy, P.E., of a compressed spring is given as follows;
P.E. = 1/2·k·x²
∴ The potential energy given to hose, P.E. = 1/2 × 88.0 N/m × (4.20 m)²
1/2 × 88.0 N/m × (4.20 m)² = 776.16 J
The work done on the hose = The potential energy given to hose, P.E. = 776.16 J
-- First question . . . first answer choice
-- Second question . . . second answer choice
-- Third question . . . third answer choice
