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Leni [432]
3 years ago
9

explain " you can not apply a force to an object with out that object applying the same force back to you"​

Physics
2 answers:
NemiM [27]3 years ago
5 0
Newton’s third law motion
stealth61 [152]3 years ago
3 0

Answer:

Newton's Third Law Of Motion

Explanation:

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Two parallel plates 19 cm on a side are given equal and opposite charges of magnitude 2.0 ✕ 10^−9 C. The plates are 1.8 mm apart
Romashka [77]

Answer:

E   = 5291.00 N/C

Explanation:

Expression for capacitance is

C = \frac{\epsilon  A}{d}

where

A is area of square plate

D = DISTANCE BETWEEN THE PLATE

C = \frac{\epsilon\times(19\times 10^{-2})^2}{1.5\times 10^{-3}}

C = 24.06 \epsilon

C = 24.06\times 8.854\times 10^{-12} F

C =2.1\times 10^{-10} F

We know that capacitrnce and charge is related as

V = \frac{Q}{C}

 = \frac{2\tiimes 10^{-9}}{2.\times 10^{-10}}

v = 9.523 V

Electric field is given as

E = \frac{V}{d}

   = \frac{9.52}{1.8*10^{-3}}

E   = 5291.00 V/m

E   = 5291.00 N/C

5 0
3 years ago
A rock at the top of a 20 meter tall hill.The rock has a mass of 10 kg. How much potentail   energy does it have?
ch4aika [34]
P.E.=mgh
= 10x10x20
=2000J
6 0
3 years ago
If you know what a JW is LET ME KNOW and it is a type of ppl
lisabon 2012 [21]

Answer:

only thing I think of when I see that is 'Just Wondering'

Explanation:

3 0
3 years ago
Read 2 more answers
Your friends sit in a sled in the snow. If you apply a force of 95 N to them, they have an acceleration of 0.8 m/s2. What is the
ss7ja [257]

F=ma
m=F/a=95/0.8= 118.75kg
your friend is pretty heavy XD
5 0
3 years ago
Read 2 more answers
A object with a mass of 1.5 kg is lifted from the ground to a height of 0.22 m what is the objects potential energy
svet-max [94.6K]

Answer:

<h2>3.3 J</h2>

Explanation:

The potential energy of a body can be found by using the formula

PE = mgh

where

m is the mass

h is the height

g is the acceleration due to gravity which is 10 m/s²

From the question we have

PE = 1.5 × 10 × 0.22

We have the final answer as

<h3>3.3 J</h3>

Hope this helps you

5 0
3 years ago
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