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2 years ago

explain " you can not apply a force to an object with out that object applying the same force back to you"

Physics

2 answers:

NemiM [27]2 years ago

5 0

Newton’s third law motion

stealth61 [152]2 years ago

3 0

Answer:

Newton's Third Law Of Motion

Explanation:

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What force is required to accelerate a body with a mass of 15 kilograms at a rate of 8 m/s²?

lawyer [7]

I really think it could be a 23 kg

4 0

3 years ago

Definition of distance in physics

solniwko [45]

Answer:

Distance is a scalar quantity that refers to "how much ground an object has covered" during its motion. Displacement is a vector quantity that refers to "how far out of place an object is"; it is the object's overall change in position.

Explanation:

8 0

2 years ago

If you wanted to know how big a tiger is, which measurements would you use?

valina [46]

Answer:

meter, kilogram

Explanation:

Here we want to know how big the tiger is. This means that we want to measure its size and possibly its mass.

The size is actually a measure of the length of the tiger, and length is measured in meters.

The mass of an object, instead, is a measure of the "amount of matter" in the substance, and it is measured in kilograms.

The other options are wrong because:

- The second is the unit of time

- The candela is the unit of the luminous intensity

- The mole is the unit of the amount of substance, and it is used for gases

- The ampere is the unit of the current

5 0

2 years ago

A 180 g model airplane charged to 18 mC and traveling at 2.2 m/s passes within 8.6 cm of a wire, nearly parallel to its path, ca

viva [34]

Answer:

$a=0.2*10^{-5}g$

Explanation:

From the question we are told that:

Mass $M=180=>0.18kg$

Charge $Q=18mC=18*10^-^3C$

Velocity $v=2.2m/s$

Length of Wire $L=8.6cm=>0.086$

Current $I=30A$

Generally the equation for Magnetic Field of Wire B is mathematically given by

$B=\frac{\mu_0*I}{2\pi*l}$

$B=\frac{4*3.14*10^-^7*I}{2*3.14*8.6}$

$B=6.978*10^{-5}T$

Generally the equation for Force on the plane F is mathematically given by

$F=qvB$

Therefore

$ma=qvB$

$a=\frac{qvB}{m}$

$a=\frac{18*10^{-5}83.4*6.978*10^{-5}}{0.18kg}$

$a=2.37*10^{-5}$

Therefore in Terms of g's

$a=\frac{2.37*10^{-5}}{9.8}$

$a=0.2*10^{-5}g$

8 0

2 years ago

What is the resistance if the current is 15 amps and the voltage 105 volts

Ludmilka [50]

I think it’s R=U/I = 120/5 = 24

3 0

2 years ago

explain " you can not apply a force to an object with out that object applying the same force back to you"​

explain " you can not apply a force to an object with out that object applying the same force back to you"